None because without an equality sign the given terms can't be considered to be an equation.
You are supposed to calculate the so-called discriminant, b2 - 4ac. If the result is positive, the equation has two real solutions; if it is zero, one real solution; if it is negative, no real solution (and two complex solutions). For this particular equation, a = 1, b = -10, and c = 25.
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
Only one. 2x - 12x = 220 -10x = 220 x= 220/-10 x = -22
46Improved answer:First rearrange this quadratic equation which will have two solutions :2x2-10x-6 = 0Simplify the equation by dividing all terms by 2:x2-5x-3 = 0Then by using the quadratic equation formula it will work out as:x = (5 + the square root of 37)/2or x = (5 - the square root of 37)/2
6.10 is the solution to the equation 10x (6.11x) 6.
An equation would be....,X2 - 10X + 16 = 0easy factoring(X - 2)(X - 8)==========So.X = 2====
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
You are supposed to calculate the so-called discriminant, b2 - 4ac. If the result is positive, the equation has two real solutions; if it is zero, one real solution; if it is negative, no real solution (and two complex solutions). For this particular equation, a = 1, b = -10, and c = 25.
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
Only one. 2x - 12x = 220 -10x = 220 x= 220/-10 x = -22
mansion
Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5
If you mean: x-3x+27 = 8x-3 then -10x = -30 and x =3
Equations: 2x-3y = 4 and 5x+2y = 1 Multiply all terms in 1st equation by 5 and all terms in 2nd equation by 2:- So: 10x-15y = 20 and 10x+4y = 2 Subtract the 2nd equation from the 1st equation: -19y = 18 => y = -18/19 By substitution the solutions are: x = 11/19 and y = -18/19
10x-2x =8x-527
1-10x = 81 -10x = 81-1 -10x = 80 x = -8
Yes because rearranging it into the form of 3x2-10x+5 = 0 makes the discriminant of the quadratic equation greater than zero which means it will have two different solutions. Solving the equation by means of the quadratic formula gives x as being 2.721 or 0.613 both corrected to 3 decimal places.