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Q: How many combination's can you get out of 12 numbers and letters?

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There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.

2,704,156

12

You would get 4!/2! = 12 combinations.

There are 24C12 = 24*23*...*13/(12*11*...*1) = 2,704,156 combinations.

30

Only three: 12, 13 and 23. Remember that the combinations 12 and 21 are the same.

26 = 64 combinations, including the null combination - which contains no numbers.

Assuming that the only permitted operation is addition, then there are 4 combinations.

3! or Just simply 3x2x1=6 combinations * * * * * Wrong! That is the number of permutations, not combinations. There are 23 combinations: 123, 12, 13, 23, 1, 2, 3 and the null combination.

There are several combinations of numbers that can answer this question. 1x12=12 2x6=12 3x4=12

11

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