3!(factorial) or six
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
There are infinitely many possible answers. Here is one: 62 + 1
With two bits, there are (2^2) possible combinations, which equals 4. The combinations are: 00, 01, 10, and 11. Each bit can be either 0 or 1, leading to these four distinct configurations.
At least 11 of them.
-2
There are millions of possible combinations.
There are eight possible combinations.
Just 1.
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
There are 1285C4 = 1285*1284*1283*1282/(4*3*2*1) = 113076300485 combinations.
There are infinitely many possible answers. Here is one: 62 + 1
With two bits, there are (2^2) possible combinations, which equals 4. The combinations are: 00, 01, 10, and 11. Each bit can be either 0 or 1, leading to these four distinct configurations.
We select 1 shirt out of 6 shirts in (6 choose 1) ways or 6 ways. Then, we select 1 out of 3 pairs of shorts in (3 choose 1) or 3 ways. Therefore, the possible combinations of a shirt and a pair of shorts is 6 * 3 = 18 possible combinations.
At least 11 of them.
To calculate the number of possible combinations of the digits 1, 3, 7, and 9, we can use the formula for permutations of a set of objects, which is n! / (n-r)!. In this case, there are 4 digits and we want to find all possible 4-digit combinations, so n=4 and r=4. Therefore, the number of possible combinations is 4! / (4-4)! = 4! / 0! = 4 x 3 x 2 x 1 = 24. So, there are 24 possible combinations using the digits 1, 3, 7, and 9.
the equal nukber would be 1000987654 but if you put it that way you will lose the stautus chart and it will mess you up i am a math teacher for 12 grade i know my stuff
want total answer possible of different sudoku 9 x 9 total amount only