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โˆ™ 2010-03-09 20:18:04
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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How many possible different combinations of numbers r possible in just the last 4 numbers?
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Related questions

How many possible combinations of six numbers are possible from six numbers?

Just 1.


How many 3 number combinations are possible with 1234?

Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.


How many combinations of 6 numbers in 6 numbers?

Just one. unless you count 123456 different from 132456 then there are 46656 * * * * * But you cannot count 123456 as different from 132456 since it is NOT a different combination. And the question was about combinations.


How many combinations are there for a 6 digit number using the numbers 0 to 9?

There are 1 million possible combinations. Just think of it as a sequence of numbers, starting at 000000, 000001... all the way to 999999.


How many different 3 item combinations can you get out of 5 different items?

whenever you have a question like this, just multiply the two numbers together and you got your answer.


How many combinations are there in 4 numbers?

10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.


How many combinations of 6 numbers are there in 56 numbers What are these combinations?

just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436


How many combinations are there of 8 numbers?

There is just 1 combination of 8 numbers taken 8 at a time.


How many different 6 digit combinations can be made from 10 numbers if you can repeat a number?

There are just 5,005.There are 10C6 = 210 combinations with 6 different numbers.There are 10C5 = 252 combinations with 5 different numbers. One of these needs to be duplicated and the one to be duplicated can be chosen in 5 ways so there are 1260 of these.There are 10C4 = 210 combinations with 4 different numbers. Either one of them appears three times or two are doubled. That can be done in 10 ways so there are 2,100 of these.There are 10C3 = 120 combinations with 3 different numbers. Either one of them appears 4 times, or one twice and another three times, or all three appear twice. That can be done in 10 ways so there are 1,200 of these.There are 10C2 = 45 combinations with 2 different numbers. Either one of them appears 5 times, or one twice and another four times, or both three times. That can be done in 5 ways so there are 225 of these.There are 10C1 = 10 combinations with just 1 number repeated six times.Add these together.


How many different combinations of 6 numbers are in the numbers 1-15?

I will presume that you are using the space of integers (as there are in infinite number of real or even rational numbers between 1 and 15). There are 15 integers on the interval of [1,15] and we want to find all possible combinations of 6 numbers from this set. We use a combination, 6C15= 15! / (6! * (15 - 6)!) = 15! / (6! * 9!) If you do not have a calculator which does factorials or combinations, then you can do some cancellations to make the computation a little easier: 15! = 15 * 14 * 13 * 12 * 11 * 10 * 9! so we can cancel the 9!, which leaves us with: 15 * 14 * 13 * 12 * 11 * 10 / 6! This is still going to involve the multiplication and division of very large numbers, so I took the pansy route and just used a calculator and got: 5,005 different possible combinations.


How many combinations of 6 numbers are there in 44 numbers?

Just use combinations formula. nCr, where n=44, r=6. Plug it into the calculator or use the formula, nCr = n!/[r!(n-r)!] And you should get 7059052 as the number of combinations.


How many combinations are there if there are 3 numbers?

3! or Just simply 3x2x1=6 combinations * * * * * Wrong! That is the number of permutations, not combinations. There are 23 combinations: 123, 12, 13, 23, 1, 2, 3 and the null combination.

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