To calculate the combinations for the numbers 2, 6, and 8, we need to use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, we have 3 numbers (n=3) and we want to choose 2 of them (r=2). So, the combinations would be 3C2 = 3! / 2!(3-2)! = 3. Therefore, the combinations for 2, 6, and 8 are (2, 6), (2, 8), and (6, 8).
Well, isn't that just lovely? With the numbers 2, 6, and 8, you can create different combinations by adding, subtracting, multiplying, or dividing them. Take your time to explore these combinations like a happy little explorer and see what beautiful creations you can come up with. Remember, there are no mistakes, just happy little accidents in the world of numbers.
There are 8 possible combinations:
{},
{2},{6},{8},
{2,6},{2,8},{6,8} and
{2,6,8}
There are 8 possible combinations:
{},
{2},{6},{8},
{2,6},{2,8},{6,8} and
{2,6,8}
There are 8 possible combinations:
{},
{2},{6},{8},
{2,6},{2,8},{6,8} and
{2,6,8}
There are 8 possible combinations:
{},
{2},{6},{8},
{2,6},{2,8},{6,8} and
{2,6,8}
Your a bum 4 lising 2 me 2 4 6 8 2 4 8 6 2 6 4 8 2 6 8 4 2 8 4 6 2 8 6 4 4 2 6 8 4 2 8 6 4 6 2 8 4 6 8 2 4 8 2 6 4 8 6 2 6 2 4 8 6 2 8 4 6 4 2 8 6 4 8 2 6 8 2 4 6 8 4 2 8 2 4 6 8 2 6 4 8 4 2 6 8 4 6 2 8 6 2 4 8 6 4 2 That's all 24 possible combinations.
There are 8!/[6!(8-6)!] = 8*7/2 = 28 - too many to list.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
From 8 numbers there are 28 possible 6 number combinations. As you are selecting 6 numbers from 8 and the order of selection doesn't matter: First, there are 8 x 7 x 6 x 5 x 4 x 3 ways that 6 numbers can be selected in order. However, as the order doesn't matter, each 6 number combinations will be selected in 6 x 5 x 4 x 3 x 2 x 1 ways. Thus there are (8 x 7 x 6 x 5 x 4 x 3) ÷ (6 x 5 x 4 x 3 x 2 x 1) = 28 different combinations.
5*6*7*8=1680
Your a bum 4 lising 2 me 2 4 6 8 2 4 8 6 2 6 4 8 2 6 8 4 2 8 4 6 2 8 6 4 4 2 6 8 4 2 8 6 4 6 2 8 4 6 8 2 4 8 2 6 4 8 6 2 6 2 4 8 6 2 8 4 6 4 2 8 6 4 8 2 6 8 2 4 6 8 4 2 8 2 4 6 8 2 6 4 8 4 2 6 8 4 6 2 8 6 2 4 8 6 4 2 That's all 24 possible combinations.
There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.
There are 8!/[6!(8-6)!] = 8*7/2 = 28 - too many to list.
With 2 6-sided dices there are 6x6=36 combinations (6 for the first dice, 6 for the second dice) Let put the question this other way: how many combinations with a total more than 8, namely 9, 10, 11 or 12 ? 9: 4 combinations: 4-5 or 5-4 or 6-3 or 3-6 10: 3 combination: 5-5 or 6-4 or 4-6 11: 2 combinations: 6-5 or 5-6 12: 1 combination: 6-6 So there are 10 combinations for "more than 9" thus there are 36-10=26 combinations for "less or equal to 8".
(8 x 7 x 6 x 5 x 4 x 3)/(6 x 5 x 4 x 3 x 2) = 28 combinations
There are 8*7/(2*1) = 28 combinations.
6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are: 8C6 = 8!/6!(8-6)! = (8 x 7)/(2 x 1) = 28.
7C3 = 7*6*5/(3*2*1) = 35 combinations.7C3 = 7*6*5/(3*2*1) = 35 combinations.7C3 = 7*6*5/(3*2*1) = 35 combinations.7C3 = 7*6*5/(3*2*1) = 35 combinations.
From 8 numbers there are 28 possible 6 number combinations. As you are selecting 6 numbers from 8 and the order of selection doesn't matter: First, there are 8 x 7 x 6 x 5 x 4 x 3 ways that 6 numbers can be selected in order. However, as the order doesn't matter, each 6 number combinations will be selected in 6 x 5 x 4 x 3 x 2 x 1 ways. Thus there are (8 x 7 x 6 x 5 x 4 x 3) ÷ (6 x 5 x 4 x 3 x 2 x 1) = 28 different combinations.
10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.