0
None because without an equality sign the given expression is not an equation and so therefore no solutions are possible.
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What is the equation for the sum of three consecutive integers is negative 87?
Since there are three numbers involved in the answer, the equation needs to have three solutions which makes it somewhat complicated. x3 + 87x2 + 1739x + 24360 = 0
How can you tell how many solutions a quadratic equation will have without solving it?
A quadratic equation can have a maximum of 2 solutions. If the discriminant (b2-4ac) turns out to be less than 0, the equation will have no real roots. If the Discriminant is equal to 0, it will have equal roots. But, if the discriminant turns out to be more than 0,then the equation will have unequal and real roots.
How many solutions will the equation 25 equals 2x squared-6x have?
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
Can any number divided by itself equal to the square of the original number?
As an equation, x/x = x2, or x2 = x/x. Multiplying both sides by x: x3 = x. Put everything on the left side: x3 - x = 0. Factoring the left part: x(x2 - 1) = 0, or x(x+1)(x-1) = 0. This has the solutions 0, 1, -1. However, 0 doesn't make sense in the original equation - it seems that multiplying with "x" introduced an extra solution.The remaining solutions, 1 and -1, fit the original specification.
How do I write an equation for a sequence that isn't linear or exponential?
A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)
How many solutions does 0 equals 0 have?
0 = 0 is an identity and not an equation. Equations have solutions, identities do not.
If the discriminant of a quadratic equation is -4 how many solutions does the equation have?
If the discriminant of a quadratic equation is less then 0 then it will have no real solutions.
What is the equation for the sum of three consecutive integers is negative 87?
Since there are three numbers involved in the answer, the equation needs to have three solutions which makes it somewhat complicated. x3 + 87x2 + 1739x + 24360 = 0
What does it mean if an equation equals 0 does it have one solution no solution or indefinitely many solutions?
It has infinitely many solutions.
What are the zeros of the polynomial function fx equals x3-4x2-12x?
Factor the equation and solve for x in each part. x3-4x2-12x Factor out an x right away x (x² - 4x - 12) factor the trinomial x (x - 6) (x + 2) now solve each for y=0 x=0, (x-6=0), (x+2=0) The zeroes (solutions) to the equation are {-2 0 6 }■
How many solutions are there to the equation below 3x - 10(x plus 2) 13 - 7x?
How many solutions are there to the equation below? 3x-10(x+2) = 13-7x 0
How many real solutions does the equation 3x2 12x 12 0 have?
If you mean: 3x^2+12x+12 = 0 then it has two equal solutions of -2
How many real solutions are there for the equation x2 plus 3x plus 5 equals 0?
There are no real solutions because the discriminant of the quadratic equation is less than zero.
How can you tell how many solutions a quadratic equation will have without solving it?
A quadratic equation can have a maximum of 2 solutions. If the discriminant (b2-4ac) turns out to be less than 0, the equation will have no real roots. If the Discriminant is equal to 0, it will have equal roots. But, if the discriminant turns out to be more than 0,then the equation will have unequal and real roots.
How many solutions will the equation 25 equals 2x squared-6x have?
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
Can any number divided by itself equal to the square of the original number?
As an equation, x/x = x2, or x2 = x/x. Multiplying both sides by x: x3 = x. Put everything on the left side: x3 - x = 0. Factoring the left part: x(x2 - 1) = 0, or x(x+1)(x-1) = 0. This has the solutions 0, 1, -1. However, 0 doesn't make sense in the original equation - it seems that multiplying with "x" introduced an extra solution.The remaining solutions, 1 and -1, fit the original specification.
How do I write an equation for a sequence that isn't linear or exponential?
A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)
