There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
the solution is the answer to the equation. A solution is any value that makes the equation true. x + 2 = 10 has exactly one solution ....x=8 x + 2 > 10 has infinitely many solutions....x=9 or 10 or 11 or 12 or 13, etc
When trying to solve an equation and you end up with the exact same number on both sides , like 10=10 then the equation has infinitely many solutions. If you end up with 2 different number on both side of the equation, like 3=5 then the equation has no solution. If there is a variable on one side and a number on the other, then there is one solution, e.g. x=4. In the equation 10=10 there is no variable such as x or y that we are trying to find the solution for. The equation x=x might be said to have an infinite number of solutions, because you can choose any value you like for x. More often you would say that "x is indeterminate". So if your equation always turns out to be satisfied for any x you choose, then there is an infinity of solutions and the equation does not represent anything useful. Or, for example, it may have a result such as "true for all even numbers", and you may not be aware in advance that this might happen. Or another example might be sin(x)=0 which has solutions for all values for those x which are integer multiples of 180 degrees. The only way is to solve the equation and see what appears.
Assuming x(2-10x)=21 to be solved for x, distribute to -10x2+2x=21, or 10x2-2x+21=0. By the quadratic equation, we can determine there are no real solutions because the square root of -836 does not exist. In imaginary solutions, we can reduce to 1/10*(1 + sqrt(-209)) and 1/10*(1-sqrt(-209)) as solutions.
If you are looking to factor x^2-6x-40 it'd be (x-10)(x+4). There are two possible solutions. (10,-4)
There are infinitely many solutions to the equation since it simplifies to 13 = 13, which is always true.
You are supposed to calculate the so-called discriminant, b2 - 4ac. If the result is positive, the equation has two real solutions; if it is zero, one real solution; if it is negative, no real solution (and two complex solutions). For this particular equation, a = 1, b = -10, and c = 25.
The equation has infinitely many solutions.
Two cases in which this can typically happen (there are others as well) are: 1. The equation includes a square. Example: x2 = 25; the solutions are 5 and -5. 2. The equation includes an absolute value. Example: |x| = 10; the solutions are 10 and -10.
There are no solutions because the discriminant of this quadratic equation is less than zero
" -10 " is just a number. It's not a question, equation, conundrum, exercise, quandary, or problem of any kind. It has no solutions, because there's nothing about it that needs any.
10
It isn't entirely clear what you mean "for 15 and 10". If you want an equation that has those solutions, you can simply write:(x - 15) (x - 10) = 0 If you wish, you can multiply the polynomials out. The solutions will be the same, but the resulting equation will be harder to solve.
The person or program that solves the equation does.
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
12
There are none because without an equality sign it can not be considered to be an equation and the + or - values of 3x and 10 are not given