It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
There are two solutions and they are: x = -1 and y = 3
It works out that the solutions are: x = 3 and y = 2
0 = 0 is an identity and not an equation. Equations have solutions, identities do not.
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
The solutions are: x = -2 and y = 4
They are called the solutions or roots of the equations.
Equations: 3x-5y = 16 and xy = 7 Solutions: (7, 1) and (-5/3, -21/5)
The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.
The equations are identical in value, ie the second is merely twice the first...
Add the two equations together. This will give you a single equation in one variable. Solve this - it should give you two solutions. Then replace the corresponding variable for each of the solutions in any of the original equations.
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
Through a process of elimination and substitution the solutions are s = 8 and x = 5
When x = -2 then y = 4 which is the common point of intersection of the two equations.
Only one: (3,-2)
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
The solutions are: x = 4, y = 2 and x = -4, y = -2
x = y = 3
There is no solution for those equations because the lines are parallel so, they never touch.
Do you want the solutions to the equations? If so then: x = 7 and y = 4
They are simultaneous equations and their solutions are x = 41 and y = -58
They are: (3, 1) and (-11/5, -8/5)