Q: How many ways can you choose 5 out of 3?

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The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.

Nine

There are 4200, in all.

There are many ways, but 5 different ways are: 3/1, 6/2, 9/3, 12/4, and 15/5.

We are asked to choose a team of 4 members consisting of two girls and two boys from a math club made up of three girls and five boys.To choose the girls, we leave one out of the team. There are 3 ways to leave one girl off the team.To choose the boys, we can choose any one of the 5 for the first and any one of the remaining 4 for the second. However it doesn't matter the order in which we choose them so we divide by 2. This gives us: 5(4)/2 = 10.This would lead to 3(10) = 30 possible ways to choose the entire team.Note: This is equivalent to 3 choose 2 * 5 choose 2 = 3 * 10 = 30.

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The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.

You can make 125 different 3-digit numbers if you're allowed to repeat a digit (for example, 113, or 545), and 60 if you're not. If repetitions are allowed, then there are 5 ways to choose each digit to be 1,2,3,4, or 5, so the total number of ways is 5*5*5 or 125. If no repetitions are allowed, there are 5 ways to choose the first digit, but only 4 ways left to choose the second (for a total of 5*4=20 ways to choose the first two digits), because it can't be the same as the first. Then you have eliminated two choices for the third digit, so there are only 3 ways to choose it, for a total of 5*4*3=60 different 3-digit numbers.

Nine

10 and btw don't use this sight :P :)

Since there are 6 numbers that equal 26 to choose from, there are 6 to choose from for the first number, 5 to choose from for the second number, 4 to choose from for the third number, and so on. Therefore there are 6*5*4*3*2*1 ways or 6! or 720.

(12 x 11 x 10 x 9 x 8)/(5 x 4 x 3 x 2) ie 792 ways.

You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.

There are 4200, in all.

Two books are compulsory, so the student really wants to know how many ways he can pick 3 out of 7. That is 35.

123 124 125 134 135 145 234 235 245 345 Total: 10

6*5*4*3 = 360 ways. http://en.wikipedia.org/wiki/Permutations

5 is. (How many different ways are there for him to notchoose one of the five ?)