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None. If you mean 3 out of 5 then 10

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βˆ™ 15y ago
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Q: How many ways can you choose 5 out of 3?
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How many ways can you purchase 2 CDs if there are 3 to choose from 4 cassettes if there are 4 to choose from and 2 DVDs if there are 5 to choose from?

The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.


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You can make 125 different 3-digit numbers if you're allowed to repeat a digit (for example, 113, or 545), and 60 if you're not. If repetitions are allowed, then there are 5 ways to choose each digit to be 1,2,3,4, or 5, so the total number of ways is 5*5*5 or 125. If no repetitions are allowed, there are 5 ways to choose the first digit, but only 4 ways left to choose the second (for a total of 5*4=20 ways to choose the first two digits), because it can't be the same as the first. Then you have eliminated two choices for the third digit, so there are only 3 ways to choose it, for a total of 5*4*3=60 different 3-digit numbers.


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Since there are 6 numbers that equal 26 to choose from, there are 6 to choose from for the first number, 5 to choose from for the second number, 4 to choose from for the third number, and so on. Therefore there are 6*5*4*3*2*1 ways or 6! or 720.


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You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.


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Two books are compulsory, so the student really wants to know how many ways he can pick 3 out of 7. That is 35.


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123 124 125 134 135 145 234 235 245 345 Total: 10


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What is the answer for Hector can choose any 4 of the 5 screensavers offered with his new computer How many different combinations of 4 screensavers could he choose?

5 is. (How many different ways are there for him to notchoose one of the five ?)