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How many ways can you purchase 2 CDs if there are 3 to choose from 4 cassettes if there are 4 to choose from and 2 DVDs if there are 5 to choose from?
The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
How many ways can you choose 5 out of 9?
Nine
How many ways can you purchase 5 cds if there are 6 to choose from2 cassettes if there are 5 to choose from and 4 cds if there are 8?
There are 4200, in all.
How do you write 3 as a improper fraction?
There are many ways, but 5 different ways are: 3/1, 6/2, 9/3, 12/4, and 15/5.
A four member math team is chosen from the math club which has 3 girls and 5 boys How many different teams made up of 2 girls and 2 boys could be chosen?
We are asked to choose a team of 4 members consisting of two girls and two boys from a math club made up of three girls and five boys.To choose the girls, we leave one out of the team. There are 3 ways to leave one girl off the team.To choose the boys, we can choose any one of the 5 for the first and any one of the remaining 4 for the second. However it doesn't matter the order in which we choose them so we divide by 2. This gives us: 5(4)/2 = 10.This would lead to 3(10) = 30 possible ways to choose the entire team.Note: This is equivalent to 3 choose 2 * 5 choose 2 = 3 * 10 = 30.
How many ways can you purchase 2 CDs if there are 3 to choose from 4 cassettes if there are 4 to choose from and 2 DVDs if there are 5 to choose from?
The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
A committee of 5 people must be selected from 5 accountants and 8 educators in how many ways can a selection be done if there are at least 3 educators in the committee?
Well, honey, if you want a committee with at least 3 educators out of 5 members, you can choose 3 educators out of 8 in 8 choose 3 ways, and then fill the remaining 2 spots with any of the remaining educators or accountants. So, that gives you 8 choose 3 * 5 choose 2 ways, which is 56 * 10 = 560 ways to create your sassy little committee.
How many 3 digit sets of numbers can be formed from the finite set of 12345?
You can make 125 different 3-digit numbers if you're allowed to repeat a digit (for example, 113, or 545), and 60 if you're not. If repetitions are allowed, then there are 5 ways to choose each digit to be 1,2,3,4, or 5, so the total number of ways is 5*5*5 or 125. If no repetitions are allowed, there are 5 ways to choose the first digit, but only 4 ways left to choose the second (for a total of 5*4=20 ways to choose the first two digits), because it can't be the same as the first. Then you have eliminated two choices for the third digit, so there are only 3 ways to choose it, for a total of 5*4*3=60 different 3-digit numbers.
How many ways can you choose 5 out of 9?
Nine
How many different ways can a person choose 3 out of 5 markers?
10 and btw don't use this sight :P :)
How many ways can six even postitive numbers equal a sum of 26?
Since there are 6 numbers that equal 26 to choose from, there are 6 to choose from for the first number, 5 to choose from for the second number, 4 to choose from for the third number, and so on. Therefore there are 6*5*4*3*2*1 ways or 6! or 720.
How many ways can you choose 5 from 12?
(12 x 11 x 10 x 9 x 8)/(5 x 4 x 3 x 2) ie 792 ways.
How many ways can you choose 2 books from 5 on a shelf?
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
How many ways can you purchase 5 cds if there are 6 to choose from2 cassettes if there are 5 to choose from and 4 cds if there are 8?
There are 4200, in all.
How many ways in which a student can choose 5 out of 9 books if 2 books are compulsory?
Two books are compulsory, so the student really wants to know how many ways he can pick 3 out of 7. That is 35.
How many possible ways are there to choose 3 of your 5 friends?
123 124 125 134 135 145 234 235 245 345 Total: 10
Suppose you find six articles related to the topic of your research paper In how many ways can you choose four articles to read?
6*5*4*3 = 360 ways. http://en.wikipedia.org/wiki/Permutations
