I assume you mean 1 and 3/4 inches in diameter. Therefore your cross-sectional area of your hose is pi/4*diameter. You can either leave your diameter in inches or convert it to feet. If you choose to leave you number in inches then you convert 100 ft to 1200 in and multiple 1200*cross-sectional area to get the cubic inches water in the hose. If you choose to convert your diameter to feet then just multiply 100 ft times cross-sectional area to get the cubic ft of water in the hose.
That section of hose holds 25.5 gallons of water when it's full, which weighs about 213 pounds. To that, add the weight of the empty hose, which I don't know.
109 lbs with no water
Pipe Diameter = 3 Inches = .25 Ft Area of Circle = Pi X D X D / 4 - where D is Diameter and Pi is 3.14159 Volume of Pipe = Length X Area = or= 1 Foot X Area Volume = [1 Ft] X [ Pi X .25 X .25 ] / 4 Volume = 0.049087 Ft3 If the 3-inch Pipe flows at 1 Foot per second, then it will carry 0.049087 Cubic Feet per second.
50 feet of 2.5-inch diameter hose has a volume of: 1.7 cubic feet (12.72 liquid gallons)
A 100-foot hose with an inside diameter of five inches can hold 102 US gallons of water.
you need more info than that. you will need to provide the length of the hose and the inside diameter of the hose to calculate the amount of water it will hold
Volume of a cylinder = (pi) x (radius)2 x (length)Radius = half of the diameter = 1.395 mm1 foot = 304.8 mmVolume = (pi) x (1.395)2 x (304.8) = 1,863.43 cubic millimeters per foot.That's about 2,031 feet of hose to hold 1 gallon of fluid ... 2.79mm is an awfully skinny hose.
Inside diameter just like copper tubing
A hose with diameter of 6 inches has cross-sectional area of [pi*r2] = pi*(3 in)21 foot = 12 inches, so (12 in)*pi*(3 in)2 = 339.292 cubic inches per linear foot of hose.Since 1 gallon = 231 cubic inches, 339.292 cubic inches = 1.46880 gallons
Depends on the water pressure, and the diameter and length of the hose. Sorry, but there really is no one answer.
The Answers community requested more information for this question. Please edit your question to include more context. You need to specify the units for the inside diameter.
1 gallon = 231 cubic inches This is a pretty skinny pipe. Diameter = 1.5 inches Radius = 0.75 inch Unit length = 1 foot = 12 inches Volume = pi R2 L = pi x (0.75)2 x 12 = pi x (0.5625) x 12 = 6.75 pi = 21.206 cubic inches = (21.206 / 231) = 0.0918 gallon per foot You need 130.7 inches = 10ft 10.7in of this pipe to hold 1 gallon.
Do you mean a fixed length of 5 inch pipe or are you asking to the amount of laminar flow through a 5 inch pipe? There is not enough info here to answer. Need length of pipe and what you are asking.
1.03 gallons
1 Gallon
It is an accepted fire service understanding that 5" Large Diameter Hose (LDH) will hold 1 gallon/ft. On average a 100' section of 5" empty weighs 110 lbs. With water weighing 8.33 lbs/gal. a 100' section of LDH filled with water will weigh approximately 944 lbs.