this problem cannot be factored
(3t + 1)(t + 5)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
(x + 5)(x + 2)
(a + x^2)(b + y^2)
(6x + 1)(x + 13)
No
6xyz(3x + 2y + z)
(6x + t)(3x + t)
(3q + 2p)(9q + 7p)
(a + 2 - b) (a + 2 + b)