It depends on whether each number is used (a) at most once, (b) exactly once or (c) as many times as you like.
The answers are
(a) 5 + 5*4 + 5*4*3 + 5*4*3*2 + 5*4*3*2*1 = 5+20+60+120+120 = 325
(b) 5*4*3*2*1 = 120
(c) infinite
1000
15
10,000
575757
When using the numbers one through seven, the total number of different combinations depends on how many numbers you want to select. If you're looking for all possible combinations of any length (from one to seven), you can calculate it using the formula for combinations, which is (2^n - 1) (where (n) is the total number of items) to account for all subsets except the empty set. Therefore, for seven numbers, there are (2^7 - 1 = 127) different combinations. If you specify a particular number of selections, the calculation would differ accordingly.
Through the magic of perms and coms the answer is 729
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
There are 360 of them.
0000 0001 0002 ... 9998 9999
Their is 25 combinations
Number of 7 digit combinations out of the 10 one-digit numbers = 120.