x + y = -2
∴ y = -2 - x
xy = 2
∴ x(-2 - x) = 2
∴ -2x - x2 = 2
∴ x2 + 2x + 2 = 0
∴ x2 + 2x + 1 = -1
∴ (x + 1)2 = -1
∴ x + 1 = i
∴ x = i - 1
recall: y = - 2 - x
∴ y = - 2 - (i - 1)
∴ y = -2 - i + 1
∴ y = - i - 1
∴ x3 + y3 = (i - 1)3 + (- i - 1)3
= (i - 1)(i2 - 2i + 1) + (- i - 1)(i2 + 2i + 2)
= i3 - 2i2 + i - i2 + 2i - 1 - i3 - 2i2 - 2i - i2 - 2i - 2
= i3 - i3 - 2i2 - i2 - 2i2 - i2 + i + 2i - 2i - 2i - 1 - 2
= -6i2 - i - 3
= 3 - i
x^3 + y^3 = (x + y)(x^2 - xy + y^2)
It is x^2 + xy + y^2
2+2y+x+xy=(x+2)(y+1)
(xy - 7)(x^2y^2 + 7xy + 49)
x3+3x2+3x+2 divided by x+2 equals x2+x+1
x^3 + y^3 = (x + y)(x^2 - xy + y^2)
It equals y+1
It is x^2 + xy + y^2
2 cubed = 2*2*2 =8. 8+8+8= 24
2 squared is 4 3 cubed is 27 27 plus 4 is 31
2+2y+x+xy=(x+2)(y+1)
(xy - 7)(x^2y^2 + 7xy + 49)
x3+3x2+3x+2 divided by x+2 equals x2+x+1
The answer is 2. 2 cubed means 2 to the 3rd power or 2x2x2 which equals 8.
if you meant 2x²+y²-xy=21x=(±sqrt(-7 y^2+168)+y)/4y=(±sqrt(-7 x^2+84)+x)/2
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2