The largest area rectangle that can be enclosed by 550 feet of Fencing is a square, which would have sides of 550/4 = 137.5 feet and therefore an area of 1.89 X 104 square feet, to the justified number of significant digits. There is no theoretical lower limit greater than zero on the area of a rectangle that would satisfy the stated conditions. As a possible practical limit, consider a rectangle with two sides each of length 273 feet and the other two sides 1 foot each. This would have an area of only 273 square feet. If the short sides could be made only 0.1 foot in length, the longer side lengths would be 274.9 feet and the area only 27.49 square feet.
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The areas are proportional to the square of the scale factor.
Knowing how to calculate areas is useful when ordering carpets, other floor coverings or quantities of turf to create a lawn. Calculating perimeters is required to order the correct length of fencing or hedging plants to enclose a garden or other area.
10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2
Find the areas of the rectangles and triangles. Add them together.
because it was estimation, the lengths were different and the rectangles are not the same
Rectangles are related to the distributive property because you can divide a rectangle into smaller rectangles. The sum of the areas of the smaller rectangles will equal the area of the larger rectangle.
multiply the length with the breadth.
Yes. Say there are two rectangles, both with perimeter of 20. One of the rectangles is a 2 by 8 rectangle. The area of this rectangle is 2 x 8 which is 16. The other rectangle is a 4 by 6 rectangle. It has an area of 4 x 6 which is 24.
rddffdg
The areas are proportional to the square of the scale factor.
Knowing how to calculate areas is useful when ordering carpets, other floor coverings or quantities of turf to create a lawn. Calculating perimeters is required to order the correct length of fencing or hedging plants to enclose a garden or other area.
10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2
It's very easy for two rectangles to have the same area and different perimeters,or the same perimeter and different areas. In either case, it would be obvious toyou when you see them that there's something different about them, and theywould not fit one on top of the other.But if two rectangles have the same area and the same perimeter, then to look at themyou'd swear that they're the same rectangle, and one could be laid down on the otherand fit exactly.
You can't tell the linear dimensions from knowing only the area. There are an infinite number of shapes that all have the same area. Even if you consider only rectangles, there are still an infinite number of different rectangles, all with different lengths and widths, that all have areas of 5,000 acres.
You need to cut up your figure into several parts in shapes for which we know how to calculate areas, such as squares, rectangles, and triangles. The area of your figure is the sum of the areas of its parts.
An L-shaped area can be divided into two rectangles. The total area is the sum of the areas of the two rectangles.