200 grams/1,000 mL x 100= 20%
684 ml
add 4 parts water per part solution
make by dissolving 2g or glucose (or dextrose) in 100 ml water or by grinding one glucose tablets (4 grams/tablet; found in drugstores) in 200ml of water.
96
4.84
the solution in the balloon is hypertonic relative to the solution in the breaker. is this true
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
Assuming that is is a solution of glucose in water, the answer is 93%.
A 30% glucose solution is purely glucose and water, though it is actually impossible to keep other contaminants out of it. To create a 30% solution of glucose, you take a fixed volume of water and add 30% of that value of glucose to the water. The amount of glucose is in grammes. For example, 3g of glucose would be added to 10ml of water.
The formula is C6H12O6 which is 180g/mole. Divide that in half for 90g in one liter of water for a 0.5 molar solution
Dissolve 100 g glucose in 1 L distilled water (or 10 g glucose in 100 mL disitlled water).
Dissolve 10 g pure glucose in 100 mL distilled water.
No,5percent glucose is an isotonic solution. 0.9 percent is for NaCl.
Not if the solution contained only glucose and water.
The administration route for norcuron is intravenously only. It can be mixed with lactated ringers, 0.9 percent NaCl solution, 5 percent glucose in saline, 5 percent glucose in water, and sterile water for injection.
Glucose is the solute; water is the solvent.
I don't think you can. The maximum solubility of glucose in water is 91% w/v. That would mean dissolving 91g of glucose in 100ml of water. for a 100% solution you would need to dissolve 100g in 100ml, and you cant do it under normal conditions.