not evenly =7 and 5/6
282 is divisible by: 1, 2, 3, 6, 47, 94, 141 and 282.
Well, darling, the smallest number you can take from 4979 to make it divisible by 47 is 6. Why? Because when you subtract 6 from 4979, you get 4973, which is divisible by 47. Simple math, honey, nothing to stress about.
No. 47 is a prime number and is only divisible by 1 and itself.
There are no numbers that are divisible by 21 but not by 7 so the "or 21" part of the question can be ignored.There are 166 numbers between 1 and 1000 that are divisible by 6. However, 23 of those are also divisible by 7.So 166 - 23 = 143 numbers.
47 is a prime number and is divisible by 1 and 47 only. 51 is divisible by 1, 3, 17, 51.
no
No. it is not
No.
No. 47 is not evenly divisible by 11.
As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
A number is divisible by 10 if its last digit is 0. To determine if a number is divisible by 235, it must be divisible by both 5 and 47 (since 235 = 5 × 47). Therefore, for a number to be divisible by both 235 and 10, it must end in 0 (for divisibility by 10) and be divisible by 47.
No. If the sum of the digits of a number is divisible by 3 then the number will be also. In this case, 9+9+8+8+7+6=47 which is not divisible by 3.