Yes you have to factor it. (3x^2+5)(2x^2-3)
x3 6x2-x-30
In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
6x2-24=0 6(x2-4)=0 x= {-2,2}
This is the equation of a parabola.
Yes.(2x)2 = 2*2*x*xor2x2 = 2 * x * x
Yes.
x3 6x2-x-30
x3 - 6x2 + 4x + 15 = (x - 3)(x - (3/2 + √29/2))(x - (3/2 - √29/2)) ⇒ roots are x = 3, x = 3/2 + √29/2 (≈ 4.19), or x = 3/2 - √29/2 (≈ -1.19)
1
In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3
6x2 - x - 15 = 0 since (6)(-15) = (-10)(9) and -10 + 9 = -1, then factor as: [(6x + 9)/3][6x - 10)/2] = 0 (2x + 3)(3x - 5) = 0 let each factor be zero: 2x + 3 = 0 or 3x - 5 = 0 solve for x: The solutions are: x = -3/2 and x = 5/3
6x2-24=0 6(x2-4)=0 x= {-2,2}
If: 6x2+11x-10 = 0 Then: x = -5/2 and x = 2/3
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
Area 36x4-64x2 and width is 6x2-8x Area = Length * width36x4 -64x2 = L * 6x2 -8x(36x4 -64x2) / (6x2 -8x) = L(36x4 -64x2) / (6x2 -8x) = L((6x2 -8x)2 + 96x3)/ (6x2 -8x) = L1 + 96x3/ (6x2 -8x) = L1 + 96x3/ x(6x -8) = L1 + 96x2/ (6x -8) = L
This is the equation of a parabola.