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Yes you have to factor it. (3x^2+5)(2x^2-3)
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How do you solve this inequality x3 6x2-x-30 Show work for x?
x3 6x2-x-30
What are the roots of the quadratic equation 6x2-x15 equals 0?
In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
What is the solution set of 6x2 24 0?
6x2-24=0 6(x2-4)=0 x= {-2,2}
Is 2x squared factorable?
Yes.(2x)2 = 2*2*x*xor2x2 = 2 * x * x
How do you solve for x in the equation 3 over x square plus 3 over 4x minus 3 over 1 equals 6 over 2x square minus 6 over 3x plus 6 over 5?
3/(x2+4x-1) = 6/(2x2-3x+5) Cross - multiply in order to eliminate the fractions: 6*(x2+4x-1) = 3*(2x2-3x+5) 6x2+24x-6 = 6x2-9x+15 6x2-6x2+24x+9x = 15+6 33x = 21 x = 21/33 => x = 7/11
Is x2 x 3 factorable?
Yes.
How do you solve this inequality x3 6x2-x-30 Show work for x?
x3 6x2-x-30
What is the root of this polynomial x3 -6x2 plus 4x plus 15?
x3 - 6x2 + 4x + 15 = (x - 3)(x - (3/2 + √29/2))(x - (3/2 - √29/2)) ⇒ roots are x = 3, x = 3/2 + √29/2 (≈ 4.19), or x = 3/2 - √29/2 (≈ -1.19)
How do you Factor x2-x 1?
1
What are the roots of the quadratic equation 6x2-x15 equals 0?
In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
What is the solution set for 6x2-x-15 equals 0?
6x2 - x - 15 = 0 since (6)(-15) = (-10)(9) and -10 + 9 = -1, then factor as: [(6x + 9)/3][6x - 10)/2] = 0 (2x + 3)(3x - 5) = 0 let each factor be zero: 2x + 3 = 0 or 3x - 5 = 0 solve for x: The solutions are: x = -3/2 and x = 5/3
What are the x-solutions for the equation below 10x2 - 56 equals 88 - 6x2?
10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3
What is the solution set of 6x2 24 0?
6x2-24=0 6(x2-4)=0 x= {-2,2}
Where does the graph of y 6x2 11x minus 10 cross the x axis?
If: 6x2+11x-10 = 0 Then: x = -5/2 and x = 2/3
Is 2x squared factorable?
Yes.(2x)2 = 2*2*x*xor2x2 = 2 * x * x
X3 plus 6x2 - 4x - 24 factor completely?
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
Area is 36x4-64x2 width is 6x2-8x what is the length in terms of x?
Area 36x4-64x2 and width is 6x2-8x Area = Length * width36x4 -64x2 = L * 6x2 -8x(36x4 -64x2) / (6x2 -8x) = L(36x4 -64x2) / (6x2 -8x) = L((6x2 -8x)2 + 96x3)/ (6x2 -8x) = L1 + 96x3/ (6x2 -8x) = L1 + 96x3/ x(6x -8) = L1 + 96x2/ (6x -8) = L
