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How do you solve this inequality x3 6x2-x-30 Show work for x?
x3 6x2-x-30
What are the roots of the quadratic equation 6x2-x15 equals 0?
In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
What is the solution set of 6x2 24 0?
6x2-24=0 6(x2-4)=0 x= {-2,2}
Is 2x squared factorable?
Yes.(2x)2 = 2*2*x*xor2x2 = 2 * x * x
How do you solve for x in the equation 3 over x square plus 3 over 4x minus 3 over 1 equals 6 over 2x square minus 6 over 3x plus 6 over 5?
3/(x2+4x-1) = 6/(2x2-3x+5) Cross - multiply in order to eliminate the fractions: 6*(x2+4x-1) = 3*(2x2-3x+5) 6x2+24x-6 = 6x2-9x+15 6x2-6x2+24x+9x = 15+6 33x = 21 x = 21/33 => x = 7/11
Is x2 x 3 factorable?
Yes.
What is the root of this polynomial x3 -6x2 plus 4x plus 15?
x3 - 6x2 + 4x + 15 = (x - 3)(x - (3/2 + √29/2))(x - (3/2 - √29/2)) ⇒ roots are x = 3, x = 3/2 + √29/2 (≈ 4.19), or x = 3/2 - √29/2 (≈ -1.19)
How do you solve this inequality x3 6x2-x-30 Show work for x?
x3 6x2-x-30
How do you Factor x2-x 1?
1
What are the roots of the quadratic equation 6x2-x15 equals 0?
In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
What is the solution set for 6x2-x-15 equals 0?
6x2 - x - 15 = 0 since (6)(-15) = (-10)(9) and -10 + 9 = -1, then factor as: [(6x + 9)/3][6x - 10)/2] = 0 (2x + 3)(3x - 5) = 0 let each factor be zero: 2x + 3 = 0 or 3x - 5 = 0 solve for x: The solutions are: x = -3/2 and x = 5/3
What are the x-solutions for the equation below 10x2 - 56 equals 88 - 6x2?
10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3
What is the solution set of 6x2 24 0?
6x2-24=0 6(x2-4)=0 x= {-2,2}
Is 2x squared factorable?
Yes.(2x)2 = 2*2*x*xor2x2 = 2 * x * x
Where does the graph of y 6x2 11x minus 10 cross the x axis?
If: 6x2+11x-10 = 0 Then: x = -5/2 and x = 2/3
What is an unfactorable polynomial?
If after finding all the factors of the product of the highest term's coefficient and the linear term, none of the can add or subtract to give the middle term then it is not factorable. x^2 +5x+6 is factorable. 1x6; 2x3 2+3=5 so it can be factored. x^2+7x+6 is factorable but x^2+8x+6 is NOT factorable because 1 and 6 as well as 2 and 3 can't add up to the middle term.
X3 plus 6x2 - 4x - 24 factor completely?
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
