Not always because 33 is divisible by 3 but not by 9
True
First Find the Sum of The Digits 9+6+2+4+0=21 So can 2,3,5, and 10 fit into 21? No so its false 2=False 3=True 5=False 10=False
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
Yes, 441 is divisible by 9. To determine if a number is divisible by 9, you can add up its digits. In this case, 4 + 4 + 1 = 9, which is divisible by 9. Therefore, 441 is divisible by 9.
Yes, the result is 7,031.
Yes, evenly 7031 times
Yes. It is also divisible by: 1 3 79 89 237 267 711 801 7031 21093 and 63279.
Look at the statement If 9 is an odd number, then 9 is divisible by 2. The first part is true and second part is false so logically the statement is false. The contrapositive is: If 9 is not divisible by 2, then 9 is not an odd number. The first part is true, the second part is false so the statement is true. Now the converse of the contrapositive If 9 is not an odd number, then 9 is not divisible by two. The first part is false and the second part is true so it is false. The original statement is if p then q,the contrapositive is if not q then not p and the converse of that is if not p then not q
3924 is divisible by 3 as the digits added together 3+9+2+4=18 is divisible by 3
False.
126 is divisible by 6 and 9
Not always because 33 is divisible by 3 but not by 9
No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6
True
Yes but it will have remainder
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.