True. The result is 7,031.
Not always because 33 is divisible by 3 but not by 9
True
First Find the Sum of The Digits 9+6+2+4+0=21 So can 2,3,5, and 10 fit into 21? No so its false 2=False 3=True 5=False 10=False
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
NO,532 is not divisible by 9.
Yes, the result is 7,031.
Yes, evenly 7031 times
Yes. It is also divisible by: 1 3 79 89 237 267 711 801 7031 21093 and 63279.
Look at the statement If 9 is an odd number, then 9 is divisible by 2. The first part is true and second part is false so logically the statement is false. The contrapositive is: If 9 is not divisible by 2, then 9 is not an odd number. The first part is true, the second part is false so the statement is true. Now the converse of the contrapositive If 9 is not an odd number, then 9 is not divisible by two. The first part is false and the second part is true so it is false. The original statement is if p then q,the contrapositive is if not q then not p and the converse of that is if not p then not q
3924 is divisible by 3 as the digits added together 3+9+2+4=18 is divisible by 3
False.
126 is divisible by 6 and 9
Not always because 33 is divisible by 3 but not by 9
No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6
True
Yes but it will have remainder
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.