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Answered 2009-02-19 13:09:21

no, but you can get a fractional answer if you divide.

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What is the divisibility rule for the number 27?

Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27


What is the LCM of 27 10 12 and 8?

Well, because it has to be a multiple of 10, you know that it has to end with a 10. The 27 is the biggest number and will be what we focus on. To get the 27 into a multiple of 10, we have to multiply it by 10.10 x 27 = 270.270 is not divisible by 12 or 8, so we continue.Keeping in mind that the number has to be a multiple of 10 and 27, we can only add intervals of 270.270+270 = 540.540 is divisible by 27, 10 and 12, but not by 8. So lets add another 270.540+270 = 810810 is only divisible by 10 and 27, much like 270, so lets add another 270.810+270 = 10801080 is divisible by 27, 10, 12 and 8 and is the lowest common multiple.


What number is 27 divisible by?

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Is 270 divisible by 10?

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What number is divisible by 27 and 36?

972 is one of the numbers that is divisible by both.


What number is divisible by 27 and 45?

1,215


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What number is divisible by 5 with a remainder of 2 and divisible by 6 with a remainder of 3?

How about 27


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What is the divisibility rule for 3?

A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, 27 = 2 + 7 = 9/3 = 3. Therefore, 27 is divisible by 3.If the sum of the digits of the number in question is divisible by three, the whole number is divisible by three.


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What number is divisible by 3 and not by 6?

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What is the smallest number which must be added to 368 to make it exactly divisible by 27?

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Is the number 5886 divisible by 9?

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If the number has a remainder of 2 when divided by 5, it must end in either 2 or 7. Because adding 10 to a number ending in 2 will not be a prime number, it must end in 7. Because you will have a prime number if you subtract 10, it must be greater than 10. The possible numbers are: 17 27 37 47 The only one of these that is divisible by 3 is 27. If you subtract 10 from 27, you have 17, which is a prime number. If you add 10 to 27, you have 37, which is a prime number. The factors of 27 are 1, 3, 9, and 27, so it has only two factors other than 1 and itself. When divided by 5, the result is 5 remainder 2. Thus, 27 fits all the conditions.