answersLogoWhite

0


Best Answer

To calculate the perimeter of a rectangle you need to add up the length of all four sides. Length + length + width + width = perimiter
2L + 2W = P

Assume L = 8, and P = 46, determine W.

2 * 8 + 2W = 46
16 + 2W = 46
subtract 16 from both sides
2W = 46 - 16
2W = 30
divide both sides by 2
W = 15.

The other side is 15 inches long.

User Avatar

Wiki User

โˆ™ 2009-11-25 15:29:48
This answer is:
๐Ÿ™
0
๐Ÿคจ
0
๐Ÿ˜ฎ
0
User Avatar
Study guides

Algebra

20 cards

A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

โžก๏ธ
See all cards

Multiplication chart! :)

12 cards

2x1

2x2

2x3

2x4

โžก๏ธ
See all cards

Math and Arithmetic

20 cards

The length of a rectangular floor is 2 feet more than its width The area of the floor is 168 square feet Kim wants to use a rug in the middle of the room and leave a 2 foot border of the floor visib

The perimeter of a rectangle is 18 feet and the area of the rectangle is 20 square feet what is the width of the rectangle

The sum of two numbers is 19 and their product is 78 What is the larger number

A rectangular garden has a perimeter of 48 cm and an area of 140 sq cm What is the width of this garden

โžก๏ธ
See all cards

Add your answer:

Earn +20 pts
Q: One side of a rectangle is 8 nches and the other side is X inches What values of X will make the perimeter at least 46 Use p equals 2l plus 2w?
Write your answer...
Submit
Related questions

How do you calculate the dimensions of a rectangle if you know the perimeter and the length?

A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.


How do you find the perimeter of a 3d rectangle?

In order to find the perimeter of a 3D rectangle you must gather the lengths of the known sides, calculate the missing rectangular values, and use the formula for perimeter.


How do you get the experimental value of a rectangle?

A rectangle has no value - experimental or otherwise. Its area has a value, its perimeter, its aspect have values.


What does the perimeter is the length plus width times two mean?

This is a simple description of finding the perimeter of a square or rectangle. It has 2 values to be added for length, and 2 to be added for width, the total sum equals the perimeter. If you add length and width and then multiply by 2 you can most likely arrive at the proper answer faster than adding the 4 values.


What values of x is the area of the rectangle greater than the perimeter?

5x> 4


One side of a rectangle is 8 inches and the other side is x inches What values of x will make the perimeter at least 46?

P = perimeter, L = length, W = width P = 2L + 2W = 2(8) + 2W = 2W + 16 = 46 2W = 30 W = 15 So as long as x is 15 inches or more, it will have a perimeter at least 46.


How do you use the formula P equals 2L plus 2W?

Perimeter of a rectangle 2L means two sides of length, thus multiply 2W means two sides of width; again multiply four sides around the rectangle and adding the L and W values gives the perimeter. Example: You have a rectangle that is 10 feet long and 6 feet wide. Find perimeter of rectangle that has 4 sides. Perimeter = 2(10 feet) + 2(6 feet) P = 20 feet + 12 feet Perimeter = 32 feet


How do you convert perimeter to area-of-rectangle?

The perimeter is 2L + 2W. The area is L x W. As long as you have one of those values, you should be able to solve for the other one.


The peremiter of a rectangle is 234 in the length exceeds the width by 39 inches find the length and width?

Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.


What is the perimeter of rectangle with an area of 54 square feet?

This has several values.The perimeter is twice the sum of any two numbers whose product is 54.


What happens when the perimeter of a rectangle is 36 inches if the length is twice the width what is the area in square inches of the rectanglr?

Since the perimeter of a rectangle is 2 * length + 2 * width, 2l + 2w = 36 And since the length is twice the width, l = 2w Thus, you substitute 2w into the l in the first equation to get, 2(2w) + 2w = 36 4w + 2w = 36 6w = 36 w = 6 Plug the value of w into the second equation, l = 2(6) This will give you a length of 12. Since the area of rectangle is l * w, we just substitute the values in for length and width, l * w = 6 * 12 = 72 And that would be in square inches of course.


Make a table of all possible whole-number pairs of lengths and width values for a rectangle with a perimeter of 18 meters?

1,8 2,7 3,6 4,5


Can you think of 5 examples where a rectangle has with the area the same as the perimeter?

Yes. Let x > 2 and calculate y = 2x/(x-2). Then the rectangle with sides x and y will have the same value for their perimeter and area, 2x2/(x-2) There are an infinity of possible values for x and so an infinite number of answers to the question.


What is the length and width of a rectangle if the perimeter is 18cm?

It is impossible to say. Let L be ANY number such that 4.5 ≤ L < 9 cm and let B = (9 - L) cm. Then for every one of the infinite number of values of L, there will be a different rectangle whose perimeter will be 18 cm.


Find the area of 12 inch and 20 inch cookie sheet?

Assuming the cookie sheet to be a rectangle, and 12 and 20 inches are the dimensions of the sheet, the area of the rectangle is s1s2. Plugging in the values yield 12(20) = 240 square inches.


What is the base and the height of a rectangle if the perimeter 24?

The perimeter of a rectangle does not provide enough information to determine its dimensions.Let 0


What rectangle has a perimeter 16 units?

Select any number, W, between 0 and 4 units.Consider a rectangle with width W and length, L = 8 - W units.Then the rectangle with dimensions L and W will have a perimeter of 16 units.Since there are infinitely many possible values for W, there are infinitely many possible answers to the question.


If a rectangle has a perimeter of 46 and the length is 11m longer than the width what is the width?

if the perimeter is 46m, then side + length = 23 so we need two values, when added together are 23, with a difference of 11 6 + 17 = 23, (and have a difference of 11) therefore the length = 17m, width = 6m


Rectangular with a perimeter of 9 cm?

There are infinitely many possible rectangles. Suppose A >= 2.25 cm is the length of the rectangle. and B = 4.5 - A cm is the width. Then perimeter = 2*(A + B) = 2*(A + 4.5 - A) = 2*4.5 = 9 cm Also, it is easy to show that A >=B so that A and B cannot swap places. For each of the infinitely many values of A, you have a rectangle with perimeter 9 cm.


What is the area of 13 and 43 inches?

To solve this, multiply the two values (assuming you mean a rectangle) This will leave you with 559in(squared)


What are all the dimensions of a rectangle if your perimeter is 36?

The length is x units and the width is 18-x units, for all values of x that are greater than 9 and less than 18 units.


Is the perimeter of a square always smaller than its area?

Units mismatch prevents any comparison of the values:perimeter is measured in units of length (e.g. inches, meters, miles)area is measured in units of area (e.g. square inches, square meters, square miles)


A rectangle with area the same as the perimeter?

The perimeter of a rectangle can be expressed as [2 * ( L+ W )]. The area of a rectangle can be expressed as [L * W]. Thus, the equation can be written as:2 * ( L + W ) = L * WThe answer originally posted on this page suggested the only solution is when the shape of the rectangle (four-sided object, opposite sides are equal length) is a square (four-sided object, all sides are equal length) with sides equal to 4.Actually, a 6 x 3 (or 3 x 6) rectangle satisfies the equation, as it has an area and perimeter both equal to 18.Keep in mind this is considering the rectangle sides must have integer values (positive number that is not a fraction), which is actually in accordance with the way the problem was posed going back to its original roots.


What is the width of the perimeter 32?

The perimeter of a shape is not sufficient information to determine its width. First of all, there is no reason to suppose that the area is rectangular as opposed to circular or triangular or some other simple or complicated shape. Even if you assume that it is a rectangle, and that the longer dimension is called the length, the width could take any one of the infinite number of values in the range (0, 8).


If the length of a rectangle is 4 feet and its perimeter is 30 feet what is its area?

The rectangle is 4 feet by 11 feet and its area is 44 square feet. (Normally the "length" would be given as the longer side.) Perimeter is the sum of the measures of the sides of a figure. The formula for the perimeter of a rectangle is P = 2L + 2W, with L standing for length and W standing for width. Simply stated, you add up the two longer sides and the two shorter sides. If the perimeter is 30 and the length is 4, you can substitute those values into the formula and solve for the unknown quantity, W, the width. So, 30 = 2(4) + 2W. Then, 2W = 22 and W = 11. Now that you know the width of the rectangle, you can find its area. The formula for the area of a rectangle is A = LW, or area equals the length times the width, measured in square units. So in this example, the area = 4 x 11 or 44 square feet. P = 2L + 2 W P = 8 + 2W = 30 2W = 30 - 8 = 22 W = 11 A = W x L = 11 x 4 = 44