To calculate the perimeter of a rectangle you need to add up the length of all four sides. Length + length + width + width = perimiter
2L + 2W = P
Assume L = 8, and P = 46, determine W.
2 * 8 + 2W = 46
16 + 2W = 46
subtract 16 from both sides
2W = 46 - 16
2W = 30
divide both sides by 2
W = 15.
The other side is 15 inches long.
A rectangle has no value - experimental or otherwise. Its area has a value, its perimeter, its aspect have values.
This is a simple description of finding the perimeter of a square or rectangle. It has 2 values to be added for length, and 2 to be added for width, the total sum equals the perimeter. If you add length and width and then multiply by 2 you can most likely arrive at the proper answer faster than adding the 4 values.
Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.
The perimeter is 2L + 2W. The area is L x W. As long as you have one of those values, you should be able to solve for the other one.
It is impossible to say. Let L be ANY number such that 4.5 ≤ L < 9 cm and let B = (9 - L) cm. Then for every one of the infinite number of values of L, there will be a different rectangle whose perimeter will be 18 cm.
In order to find the perimeter of a 3D rectangle you must gather the lengths of the known sides, calculate the missing rectangular values, and use the formula for perimeter.
A rectangle has no value - experimental or otherwise. Its area has a value, its perimeter, its aspect have values.
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
5x> 4
This is a simple description of finding the perimeter of a square or rectangle. It has 2 values to be added for length, and 2 to be added for width, the total sum equals the perimeter. If you add length and width and then multiply by 2 you can most likely arrive at the proper answer faster than adding the 4 values.
Perimeter of a rectangle 2L means two sides of length, thus multiply 2W means two sides of width; again multiply four sides around the rectangle and adding the L and W values gives the perimeter. Example: You have a rectangle that is 10 feet long and 6 feet wide. Find perimeter of rectangle that has 4 sides. Perimeter = 2(10 feet) + 2(6 feet) P = 20 feet + 12 feet Perimeter = 32 feet
P = perimeter, L = length, W = width P = 2L + 2W = 2(8) + 2W = 2W + 16 = 46 2W = 30 W = 15 So as long as x is 15 inches or more, it will have a perimeter at least 46.
Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.
The perimeter is 2L + 2W. The area is L x W. As long as you have one of those values, you should be able to solve for the other one.
Select any number, W, between 0 and 4 units.Consider a rectangle with width W and length, L = 8 - W units.Then the rectangle with dimensions L and W will have a perimeter of 16 units.Since there are infinitely many possible values for W, there are infinitely many possible answers to the question.
It is impossible to say. Let L be ANY number such that 4.5 ≤ L < 9 cm and let B = (9 - L) cm. Then for every one of the infinite number of values of L, there will be a different rectangle whose perimeter will be 18 cm.
Since the perimeter of a rectangle is 2 * length + 2 * width, 2l + 2w = 36 And since the length is twice the width, l = 2w Thus, you substitute 2w into the l in the first equation to get, 2(2w) + 2w = 36 4w + 2w = 36 6w = 36 w = 6 Plug the value of w into the second equation, l = 2(6) This will give you a length of 12. Since the area of rectangle is l * w, we just substitute the values in for length and width, l * w = 6 * 12 = 72 And that would be in square inches of course.