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One side of a rectangle is 8 nches and the other side is X inches What values of X will make the perimeter at least 46 Use p equals 2l plus 2w?
To calculate the perimeter of a rectangle you need to add up the length of all four sides. Length + length + width + width = perimiter
2L + 2W = P
Assume L = 8, and P = 46, determine W.
2 * 8 + 2W = 46
16 + 2W = 46
subtract 16 from both sides
2W = 46 - 16
2W = 30
divide both sides by 2
W = 15.
The other side is 15 inches long.
What else can I help you with?
How do you get the experimental value of a rectangle?
A rectangle has no value - experimental or otherwise. Its area has a value, its perimeter, its aspect have values.
What does the perimeter is the length plus width times two mean?
This is a simple description of finding the perimeter of a square or rectangle. It has 2 values to be added for length, and 2 to be added for width, the total sum equals the perimeter. If you add length and width and then multiply by 2 you can most likely arrive at the proper answer faster than adding the 4 values.
Is it possible to have a perimeter of 46 and an area of 42 as a rectangle?
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
The peremiter of a rectangle is 234 in the length exceeds the width by 39 inches find the length and width?
Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.
How do you convert perimeter to area-of-rectangle?
The perimeter is 2L + 2W. The area is L x W. As long as you have one of those values, you should be able to solve for the other one.
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
How do you find the perimeter of a 3d rectangle?
In order to find the perimeter of a 3D rectangle you must gather the lengths of the known sides, calculate the missing rectangular values, and use the formula for perimeter.
How do you get the experimental value of a rectangle?
A rectangle has no value - experimental or otherwise. Its area has a value, its perimeter, its aspect have values.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
What values of x is the area of the rectangle greater than the perimeter?
5x> 4
How do you use the formula P equals 2L plus 2W?
Perimeter of a rectangle 2L means two sides of length, thus multiply 2W means two sides of width; again multiply four sides around the rectangle and adding the L and W values gives the perimeter. Example: You have a rectangle that is 10 feet long and 6 feet wide. Find perimeter of rectangle that has 4 sides. Perimeter = 2(10 feet) + 2(6 feet) P = 20 feet + 12 feet Perimeter = 32 feet
What does the perimeter is the length plus width times two mean?
This is a simple description of finding the perimeter of a square or rectangle. It has 2 values to be added for length, and 2 to be added for width, the total sum equals the perimeter. If you add length and width and then multiply by 2 you can most likely arrive at the proper answer faster than adding the 4 values.
One side of a rectangle is 8 inches and the other side is x inches What values of x will make the perimeter at least 46?
P = perimeter, L = length, W = width P = 2L + 2W = 2(8) + 2W = 2W + 16 = 46 2W = 30 W = 15 So as long as x is 15 inches or more, it will have a perimeter at least 46.
Is it possible to have a perimeter of 46 and an area of 42 as a rectangle?
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
The peremiter of a rectangle is 234 in the length exceeds the width by 39 inches find the length and width?
Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.
How do you convert perimeter to area-of-rectangle?
The perimeter is 2L + 2W. The area is L x W. As long as you have one of those values, you should be able to solve for the other one.
The perimeter of a rectangle is 72m the width of the rectangle is 16m what is the area of the rectangle?
To find the area of a rectangle, you need to know the formula: Area = length x width. Given that the perimeter is 72m and the width is 16m, we can calculate the length by using the formula for perimeter of a rectangle: Perimeter = 2(length + width). Substituting the values we have, 72 = 2(length + 16), which simplifies to length + 16 = 36. Therefore, the length of the rectangle is 20m. Finally, the area of the rectangle is 20m x 16m = 320 square meters.
