P = perimeter, L = length, W = width
P = 2L + 2W = 2(8) + 2W = 2W + 16 = 46
2W = 30
W = 15
So as long as x is 15 inches or more, it will have a perimeter at least 46.
For a fixed perimeter, the area will always be the same, regardless of how you describe the rectangle.
52 ft
47
52 (13•4)
Assuming no fractional dimensions, least possible area would be a rectangle measuring 1cm x 9cm. Area increases to a maximum of 25 sq cm when shape is square, ie 5cm x 5cm.
what is the value of x so that the perimeter of the rectangle shown is at least 92 centimeters
square
For a fixed perimeter, the area will always be the same, regardless of how you describe the rectangle.
52 ft
47
52 (13•4)
If you restrict yourself to integers, the answer is 24 feet.
rectangle with 10" length and 2x-4 width 60" area
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
Whether that's the length, the width, the diagonal, or the perimeter, you don't have enough information. To get the area of a rectangle, you need at least two measurements.
The least perimeter is attained when the rectangle is, in fact a square. A square with an area of 32 square feet will have sides of sqrt(32) = 4*sqrt(2) ft. So the perimeter of the square will by 4*4*sqrt(2) = 16*sqrt(2) = 22.63 feet, approx.
For a given area a circle has least perimeter. eg Let area = 100 sq cms. For the square or rectangle the perimeter = 40 cms For the circle the radius is square root of 100/3.1416 = 5.64 and the circumference = 2 x radius x 3.1416 = 35.44 cms