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x3 + 343 = 0

(x + 7)(x2 - 7x + 49) = 0

So x = -7 or x = [7 +/- sqrt(-147)]/2

The latter two roots are [7 +/- 7i*sqrt(3)]/2

or 7/2*[1 +/- i*sqrt(3)]

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Q: Solve the equation Find all roots real and complex of x³ plus 343 equals 0?
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