x3 + 343 = 0
(x + 7)(x2 - 7x + 49) = 0
So x = -7 or x = [7 +/- sqrt(-147)]/2
The latter two roots are [7 +/- 7i*sqrt(3)]/2
or 7/2*[1 +/- i*sqrt(3)]
The complex roots of an equation are the complex numbers that are solutions to the equation.
The roots of the quadratic equation are the x-intercepts of the curve.
By using the quadratic equation formula
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
If the discriminant is negative, the roots will be two unreal complex conjugates. If the discriminate is positive the roots will be real.
The complex roots of an equation are the complex numbers that are solutions to the equation.
There are no real root. The complex roots are: [-5 +/- sqrt(-3)] / 2
No real roots but the roots are a pair of complex conjugates.
It has two complex roots.
The roots of the quadratic equation are the x-intercepts of the curve.
By using the quadratic equation formula
Because it's part of the quadratic equation formula in finding the roots of a quadratic equation.
The complex roots of an equation is any solution to that equation which cannot be expressed in terms of real numbers. For example, the equation 0 = x² + 5 does not have any solution in real numbers. But in complex numbers, it has solutions.
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
It is a quadratic equation with no real roots or real solutions. In the complex domain, the solutions are 1 +/- i where i is the imaginary square root of -1.
If the discriminant is negative, the roots will be two unreal complex conjugates. If the discriminate is positive the roots will be real.