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How do i solve y f 1 2x?
The solution to the equation y = 1/2x will be x= 2y.
What is substitution of 4x-3y equals 1 x-2y equals 4?
To solve this system of equations using substitution, we can isolate one variable in one equation and substitute it into the other equation. From the second equation, we can express x in terms of y as x = 4 + 2y. Then, substitute this expression for x into the first equation: 4(4 + 2y) - 3y = 1. Simplify this equation to solve for y. Once you find the value of y, substitute it back into x = 4 + 2y to find the corresponding value of x.
How do you solve x equals -2y?
As an equation, x = -2y cannot be solved without further information. To solve an equation (or multiple equations), the number of unknowns (x, y etc.) must be equal to or less than the number of equations. In your example you have 2 unknowns and 1 equation, so it does not work.
X plus 2y equals 11 3x-4y equals -17?
This is a system of two linear equations: x+2y=11 3x-4y=-17 One way to solve this system is to solve for x (or y) in the first equation and then plug it into the second equation to solve for the other variable, which then allows us to solve for our original variable. (1) Take the first equation and solve for x: x=11-2y (2) Plug this value into the second equation: 3x-4y=3(11-2y)-4y=33-10y=-17. We see that y=5. (3) We now plug this into either equation to solve for x: From (1): x=11-2y=11-2(5)=1 We get x=1 and y=5. It's also always a good idea to plug the numbers we found into our original two equations to verify they work. Indeed, x+2y=1+2(5)=1+10=11, and 3x-4y=3(1)-4(5)=3-20=-17.
Solve this equation 80 3y plus 2y plus 4 plus 1?
If you mean: 80 = 3y+2y+4+1 then 80 =5y+5 and so y = 15
How do you solve x y0 5x 2y -3?
To solve the equation ( xy^0 + 5x + 2y - 3 = 0 ), note that ( y^0 = 1 ), simplifying the equation to ( x + 5x + 2y - 3 = 0 ) or ( 6x + 2y - 3 = 0 ). Rearranging gives ( 2y = 3 - 6x ), leading to ( y = \frac{3 - 6x}{2} ). This represents a linear relationship between ( x ) and ( y ).
How do solve for x-2y equals -4 and 2x-y equals 1?
x - 2y = -4 2x - y = 1 To solve, multiply both sides of 2nd equation by -2 (remember if you do the same thing to both sides you do not change the equation), then add equations. x - 2y = -4 -4x + 2y = -2 adding, -3x = -6 divide by -3 both sides x = 2 substitute x = 2 into 2nd equation 2(2) - y = 1 4 -y = 1 -y = -3 y = 3 Ans: x = 2, y = 3
Solve this equation using substitution 5x plus y equals 1 and 3x plus 2y plus 2?
It is not possible to do so because the question contains one equation (5x + y = 1) and one expression (3x + 2y + 2). An expression cannot be solved.
What are the solutions to the simultaneous equations of x -2y equals 1 and 3xy -y squared equals 8 showing all appropiate work with answers?
If: x-2y = 1 and 3xy -y^2 = 8 Then: x = 1+2y and 3(1+2y)y -y^2 = 8 Hence: 3y+6y^2 -y^2 = 8 => 5y^2 +3y -8 = 0 Solving the above quadratic equation: y =1 or y = -8/5 Solutions by substitution are: when y=1 then x=3 and when y=-8/5 then x=-11/5
How do you solve 2x-2y equals 1?
get it to y= -2y = 1 - 2x y = x - 0.5
How do you solve this problem 2y plus 7x plus y - 1?
2y + 7x + y-1?
Solve this equation using addition method -8x plus 3y equals -5 and 8x subtract 2y equals 6?
x=1, y=1
