Yes, it is.
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
It also equals 13 12.
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
Yes. (Theta in radians, and then approximately, not exactly.)
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
0.75
copy this and paste in your browsers address window http://www.wolframalpha.com/input/?i=tan+theta+%2B+sec+theta+%3D1
I assume. Since theta is a variable, standing for the measure of any angle.
whats the big doubt,cot/tan+1= 1+1= 2
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)
The tangent function (tan) in trigonometry is defined as the ratio of the length of the opposite side to the length of the adjacent side in a right triangle. Mathematically, it can be expressed as ( \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} ). Additionally, in terms of sine and cosine, ( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} ), where ( \theta ) is an angle in a right triangle or in the unit circle.
The identity for tan(theta) is sin(theta)/cos(theta).