Your equation must be in y=ax^2+bx+c form
Then the equation is x= -b/2a
That is how you find the axis of symmetry
Line of symmetry: x = 3
D
x=-b/2a [negative B over 2A]
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
-1
X=-b/2a
To determine if a graph is symmetric with respect to the x-axis, check if replacing (y) with (-y) in the equation yields an equivalent equation. For y-axis symmetry, replace (x) with (-x) and see if the equation remains unchanged. For origin symmetry, replace both (x) with (-x) and (y) with (-y) and verify if the equation is still the same. If the equation holds true for any of these conditions, the graph exhibits the corresponding symmetry.
The coordinates of the vertex of a parabola, given by the equation ( y = ax^2 + bx + c ), are found at the point ((h, k)), where (h = -\frac{b}{2a}). The axis of symmetry of the parabola is a vertical line that passes through the vertex, represented by the equation ( x = h ). Thus, the x-coordinate of the vertex directly determines the equation of the axis of symmetry.
12 x 5 = 60
Line of symmetry: x = 3
D
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.
x=-b/2a [negative B over 2A]