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Q: The length of a rectangle is 5 more then the width Find the perimeter and the area of the rectangle?

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The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

you need length and width length multiply width = area length + length + width + width = perimeter

Length + length + width + width = perimeter. Length + width x 2 = perimeter

perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in

Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length

You divide the perimeter by the width and you get the lenght

Length = (Perimeter - twice width) / 2

2*length + 2*width

length 18 width 7

by appying 2l+2w

Perimeter = 2*(L + W).

dont is answer

The width is 10.5 cm.

In the simplified format:Perimeter of a rectangle = (Length) + (Width) + (Length) + (Width)In the advanced format:Perimeter of a rectangle = 2 x (Length + Width)

a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?

Subtract two times the length from the perimeter and divide the remainder by two. This should be the width.

Use the following formulae: Area = length x width Perimeter = 2 x length plus 2 x width, or length + length + width + width

You can't: perimeter = 2 x (length + width), assuming you're talking about a rectangle.

You multiply the length by 2 (because there are two sides of the rectangle that have that measure). You then subtract that number from the perimeter. The number you will be left with is twice the width, so you divide that by two and you get the width of the rectangle.

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

The perimeter is found by multiplying the width by the length. So divide 50 by 12 and you get 4.166 width.

Multiply length by width

To find the perimeter of a rectangle simply add the length and width then double your answer.

Its impossible to isolate both the length and width, but you can figure out the sum of one pair of length and width, which is 13.