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The product of three positive integers is 42 The sum of two of these integers is 9 the third integer is A1 B7 C6 D3 or E2?
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D3.
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Agrodipto Chowdhury
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What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
FIND Three consecutive integers such that the sum of the second and the third is 17 Which equation would be used to solve this word problem?
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
How do you find the product of three negative integers?
1. find the product of the first two 2. multiply that product with the third number
If the first and third of three consecutive odd integers are added the result is 51 less than 5 times the second integer Find the third integer?
Integers are x, x + 2 and x + 4. 2x + 4 = 5x + 10 - 51 3x = 45 so x = 15 and the other integers are 17 and 19. Check: 15 + 19 = 34, 5 x 17 = 85, 85 - 51 = 34. There you have it.
Find four consecutive integers such that the sum of the second and fourth is 132 show the work?
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
Is the product of an integer is an integer?
It is not possible to have the product of an integer. "product" is a binary operation and that means that it is an operation that combines two numbers to make the product - a third number. So you need two numbers as input, not just one.
Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?
The let statement is: let the smallest of the three integers be x.
How do you do integers greatest to least?
Positive integers are greater than negative integers. For positive integers: * The integer with more digits is larger. * If two integers have the same length, compare the first digit. If the first digit is the same, compare the second digit, then the third, etc., until you find a difference. In each case, the integer with the larger digit (at the first position where you find a difference) is the larger one.
What are the rules for putting integers in order from least to greatest?
First, separate the negative and positive integers (put them into two separate groups). If there is a zero, you can put it in its own group - or put it into the same group with the positive integers. Negative integers come first, then zero, then positive integers.For positive integers:An integer with less digits comes before an integer with more digits.For integers with the same number of digits, look at the first digit. The integer with the smaller digit in this position comes first.If the first digit is the same, look at the second digit. If those are equal, look at the third digit, etc.For negative integers, it is the other way round - for example, an integer with MORE digits comes first.
Is a to the 3rd power greater than or equal to a for all integer values of A and why?
No. A negative integer raised to the third power will yield a negative number that is less than the integer. Only whole numbers (positive integers greater than or equal to 1) have the property where that integer raised to the third power is greater than or equal to the integer.
Are 4 and one third both integers?
4 is an integer. 1/3 is not an integer. Only whole numbers (1, 2, 3, -1, 500, 1,999, etc.) can be integers.
What is the sum of three consecutive even integers if the sum of the first and third is 128?
The second integer is 64 (128/2), so the first is 62 and the third is 66.OrLet the 1st integer be x and the 3rd integer be y.Since even integers differ by 2, then we have:y = x + 4x + y = 128x + x + 4 = 1282x = 124x = 62So the integers are 62, 64, and 66, and their sum is 192
FIND Three consecutive integers such that the sum of the second and the third is 17 Which equation would be used to solve this word problem?
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
The sum of three integers is 69 If the first integer is doubled the sum is 77 If the second integer is doubled the sum is 91 Find the integers?
The first integer must equal 77 - 69 = 8 , since doubling it increases the sum by this amount. Similarly, the second integer must = 91 - 69 = 22. Then the third integer is 69 - 22 - 8 = 39.
How do you find the product of three negative integers?
1. find the product of the first two 2. multiply that product with the third number
The sum of four consecutive integers is 90what is the value of the third integer?
Let the first integer be x. Since the consecutive integers differ by 1, the other consecutive integers would be (x + 1), (x + 2), and (x + 3). So we havex + x + 1 + x + 2 + x + 3 = 904x + 6 = 904x + 6 - 6 = 90 - 64x = 844x/4 = 84/4x = 21Thus, the third integer is 23 (21 + 2 = 23).
