Integers are x, x + 2 and x + 4.
2x + 4 = 5x + 10 - 51
3x = 45 so x = 15 and the other integers are 17 and 19.
Check: 15 + 19 = 34, 5 x 17 = 85, 85 - 51 = 34. There you have it.
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
10-11-12
Let the smaller integer be x, then then larger integer is x + 2, and: 3x + (x + 2) = 58 → 4x = 56 → x = 14 → The two integers are 14 and 16.
First, an equation is needed. We will designate the first integer as N, and the second as N + 2. The sum of the two numbers is 176, so the equation should look like this:N + N + 2 = 176Now it needs to be added:2N + 2 = 176Now both sides need to be subtracted by 2:2N = 174Now both sides need to be divided by 2:N = 87Therefore, the first integer is 87. Since the second integer is designated by N + 2, and N is equal to 87, the second integer is 87 plus 2, which is equal to 89.So the two consecutive odd integers whose sum is 176, are 87 and 89.
51
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
They are 14, 16 and 18.
10-11-12
The numbers are 14, 16 and 18.
The let statement is: let the smallest of the three integers be x.
Let the first integer be x. The second consecutive integer would then be x+1. The sum of these two integers is x + (x+1) = 15. Simplifying, we get 2x + 1 = 15. Solving for x, we find that x = 7. Therefore, the two consecutive integers are 7 and 8.
Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.
The second integer is 51.The integers are 50, 51, and 52, so therefore the second integer is 51. This problem can be solved using this method:(x) + (x+1) + (x+2) = 1533x + 3 = 1533x = 150x = 50If x = 50, then (x+1) = 51, and (x+2) = 52.
There are no such consecutive integer as is so simple to prove! Suppose the first integer is x. Then the next (consecutive) integer is x+1. Then 2*x + 4*(x+1) = 30 So that 2x + 4x + 4 = 30 6x + 4 = 30 6x = 30 - 4 = 26 x = 26/6 which is NOT an integer.
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3