I assume this is the question in algebraic terms:
4[x+(x+1)] -4 = (x)(x+1)
4[2x+1] = x^2 + x + 4
8x+4 = x^2 + x + 4
8x = x^2 + x
7x = x^2
7 = x^2/x
7 = x
Therefore the integers are 7 and (7+1) = 8
Answer: 7 and 8
One possible answer is -4 and -3.
The 3 consecutive odd positive integers are 7, 9 and 11.
They are -10 and -9.
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
9240 is the product of the three consecutive integers 20, 21, and 22.
The product of two consecutive integers is 132. Find the two integers. They are: 11*12 = 132
One possible answer is -4 and -3.
The 3 consecutive odd positive integers are 7, 9 and 11.
Yes, the integers are 12 and 13.
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
They are are 7 and 8.
They are -10 and -9.
The product of two consecutive even integers is 840.find these numbers
-10, -9 and -8
13 & 15
11 and 13