y = 2x - 2
Point-slope form is just another way to express a linear equation. It uses two (any two points that fall on the line) and the slope of the line (Therefore the name point-slope form).y2 - y1 = m(x2 - x1)...with m as the slope.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
Point-slope form is written as: y-y1=m(x-x1), where (x1, y1) is a point on the line and m is the slope (hence the name, point-slope form).
Point slope form is standard form. To change point slope form into general form, simply multiply both sides by the denominator of the slope, and move everything onto one side.
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
y = 2x + 1.
Point-slope form is just another way to express a linear equation. It uses two (any two points that fall on the line) and the slope of the line (Therefore the name point-slope form).y2 - y1 = m(x2 - x1)...with m as the slope.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
the slope of a line is 9/5 the y intercept is -4, express the equation of the line in point slope form
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
Point-slope form is a form to express a straight line. You begin with knowing the slope, m, of a line and a point (x1,y1). It is then expressed y - y1 = m(x - x1). Another form is slope intercept expressed as y=mx+b where b is the y-intercept.
Point-slope form is written as: y-y1=m(x-x1), where (x1, y1) is a point on the line and m is the slope (hence the name, point-slope form).
Point slope form is standard form. To change point slope form into general form, simply multiply both sides by the denominator of the slope, and move everything onto one side.
no it is different
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
point slope form is y-y1=m(x-x1). x1 and y1 are both points and m is the slope.