Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35
The integers are 37, 38 and 39.
27 + 28 + 29 + 30 = 114
118
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
There are no three consecutive odd integers who's sum equals 13.
The integers are 37, 38 and 39.
The consecutive odd integers for 114 are 37, 38 and 39.
Three consecutive integers have a sum of 12. What is the greatest of these integers?
27 + 28 + 29 + 30 = 114
There is no set of three consecutive integers whose sum is 71.
118
The sum of three consecutive integers is -72
The integers are 27, 28, 29 and 30.
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
There are no three consecutive odd integers who's sum equals 13.
The numbers are 56 and 58.
27, 28, 29 and 30