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Q: There are 4 numbers the probability of spinning the number 3 is what?

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In general, you cannot. The answer depends on the shape of the spinner - how many sides it has and what numbers are on it.

The probability is 3 out of 10.

The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.

The probability is 3/7.

If each of the numbers on the spinner is equally likely, then the answer is 0.3

It depends on the number of numbers on the spinner and what those numbers are.

its the number of odd numbers (3) divided by the total number of numbers (6) 3/6 = 0.5

If it is a fair spinner, then 3/8

The prime numbers from one to nine are 2, 3, 5, and 7. There are nine numbers from one to nine. The probability is 4 (the number of prime numbers) over 9 (the total number of numbers). Therefore, the probability of choosing a prime number is 4/9 or about 44 percent.

Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60

the first 10 whole numbers are numbers 1 to 10 and in those numbers only 3 numbers are divisible by 3 in which 3, 6 and 9 therefore the probability of from those figures that the numbers won't be divisible by 3 is 7/10 or 70%.

"The probability of getting a prime number in a die is 4/6" Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.

3/16

Well, numbers divisible by 2 are even numbers, and the even numbers from 1 to 6 are 2,4,and 6. Since there are 3 out of 6 even numbers on a number cube, there is a probability 1/2 to roll an even number on a number cube.

8 numbers in total, 4 of those numbers are odd (1, 7, 5 and 3) so 4/8 = 1/2 aka 50%, 0.5

A die has 6 sides with the numbers 1,2,3,4,5 and 6. Three of those numbers are even. So the probability of rolling an even number is 3 out of 6, or 1 out of 2.

Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.

Total numbers on the cube = 6 Numbers less than 5 = 4 Probability = 4/6 = 2/3 = 662/3 %

It is possible to create a 3-digit number, without repeated digits so the probability is 1.

The three prime numbers on the cube are: 2 3 and 5 so the probability is 3/6 or 1/2 simplified

3 out of 4

Divide the number of possible even numbers by all the possible numbers. So there are three possible even numbers; 2, 4 & 6. And there are six possible numbers; 1, 2, 3, 4, 5, & 6. So the probability of throwing an even number is 3/6 = .5 .

1/3

The probability of rolling a 4 is 1/6. (There are 6 numbers one of which is "4")The probability of rolling an odd number is 3/6 = 1/2 (There are 6 numbers 3 of which are odd)Thus, in one roll of the die, the odds of rolling a 4 oran odd number = 1/6 + 3/6 = 4/6 = 2/3.

Probability of a = number of a/total number = 3/8