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Let the first of the three odd consecutive integers be x, so that the second of these integers would be x + 2, and the third one would be x + 4. We have:

3x = 2[(x + 2)+ (x + 4)] + 3

3x = 2(2x + 6) +3

3x = 4x + 12 + 3 (subtract 4x to both sides)

-x = 15 (multiply by -1 to both sides)

x = -15 (the first one)

So the integers are -15, -13, and -11.

The average of those integers is (-15 + -13 + -11)/2 = -39/2 = -19.5.

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โˆ™ 2009-12-29 18:44:11
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Q: Three times the first of three consecutive odd integers is three more than the twice and the third What is the average of the three integers?
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