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Three times the first of three consecutive odd integers is three more than the twice and the third What is the average of the three integers?
Wiki User
∙ 14y ago
Let the first of the three odd consecutive integers be x, so that the second of these integers would be x + 2, and the third one would be x + 4. We have:
3x = 2[(x + 2)+ (x + 4)] + 3
3x = 2(2x + 6) +3
3x = 4x + 12 + 3 (subtract 4x to both sides)
-x = 15 (multiply by -1 to both sides)
x = -15 (the first one)
So the integers are -15, -13, and -11.
The average of those integers is (-15 + -13 + -11)/2 = -39/2 = -19.5.
Wiki User
∙ 14y ago
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Find three consecutive odd positive integers so that the product of the first two is three less than six times the largest?
The 3 consecutive odd positive integers are 7, 9 and 11.
What three consecutive integers have a sum of 43?
Let x be the first integer. Then the sum of the three consecutive integers is x + (x+1) + (x+2), which equals 3x + 3. We are given that this sum is 43, so we can write the equation 3x + 3 = 43. Solving this equation, we find that x = 13. Therefore, the three consecutive integers are 13, 14, and 15.
What is the sum of the first four non-negative consecutive even integers?
The sum of the first four non-negative, consecutive, even integers is 20.
The sum of three consecutive even integers is 114?
Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.
Find three consecutive even integers such that the sum of the first twice the second and three times the third is 124?
18, 20 and 22
Find three consecutive odd positive integers so that the product of the first two is three less than six times the largest?
The 3 consecutive odd positive integers are 7, 9 and 11.
What is 0123?
The first four consecutive nonnegative integers. One-hundred and twenty-three with a leading zero.
What three consecutive integers have a sum of 43?
Let x be the first integer. Then the sum of the three consecutive integers is x + (x+1) + (x+2), which equals 3x + 3. We are given that this sum is 43, so we can write the equation 3x + 3 = 43. Solving this equation, we find that x = 13. Therefore, the three consecutive integers are 13, 14, and 15.
What is the sum of the first four non-negative consecutive even integers?
The sum of the first four non-negative, consecutive, even integers is 20.
What are the integers There are three consecutive multiples of nine The sum of the first two numbers is 2853?
1422, 1431, 1440
The sum of three consecutive even integers is 114?
Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.
Find three consecutive even integers such that the sum of the first twice the second and three times the third is 124?
18, 20 and 22
The sum of 3 consecutive even integers is 54 What is the first consecutive integer?
The first integer is 17.
What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
Five times the first of three consecutive even integers is 14 more then 3 times the second?
Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.
What are three consecutive integers adding up to 51?
First find the number which is 1/3 of 51. This is 17. Thus any three numbers which average 17 will always add up to 51. For the numbers to be consecutive and have an average of 17, the middle number must be 17 and the two remaining numbers are 17-1 and 17+1 ie 16 and 18. So the three consecutive numbers are 16, 17 and 18.
How do you setup a consecutive integer problem?
the first number is x, the second x+1, third, x+2 and so on.so if the sum of three consecutive integers is 24, the setup would be this:x+x+1+x+2=24if it's consecutive even or odd integers the setup would be x, x+2, x+4,etc.so if the sum of three consecutive odd integers is 21, the setup would be:x+x+2+x+4=21for three or more even consecutive numbers, same setup
