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Dimensions of a kleenex box?
The dimensions of a Kleenex box are length, width and height. The volume of the box is equivalent to length times width times height.
What is the diagonal length of a box 50 X 50?
If it is a 2-D box then 70.71
If a box has a height of 56 inches what would the length of the diagonal be?
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
What is 18 feet by 16 feet by 18?
the asnwer: a box, the volume of a box is defined by length x width x height or lxwxh, thus, something having dimensions of # by # by # is a box.
Which is length width height?
They can be the dimensions for example of a box
What is the formula for the calculation of the volume of a box?
A box is generally thought of as having three dimensions. It has length, height and depth. Some might say length, width and height, which we'll use here. In this case, the volume is the product of the three dimensions. Vbox = l x w x h
How many dimensions does the box have?
3: length, width, and height
How do you figure linear dimensions of a box?
By adding all three sides (length, breadth and height) all-together we get the linear dimensions of a box.
How long is the diagonal of a rectangle with the dimentions of 12ft by 4ft by 8ft?
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
How do you find the height of a rectangular box when length is 7 m and width is 5 m and diagonal length 10m?
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
How do you get the dimension of the box when it is given the length and the volume of the box?
You do not have enough information to calculate all three box dimensions.
How do you find the dimensions of a box that is 2 cm in height 1 cm in width and 4 cm in length?
It sounds like you have already found the dimensions of the box.
