The dimensions of a Kleenex box are length, width and height. The volume of the box is equivalent to length times width times height.
If it is a 2-D box then 70.71
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
the asnwer: a box, the volume of a box is defined by length x width x height or lxwxh, thus, something having dimensions of # by # by # is a box.
They can be the dimensions for example of a box
A box is generally thought of as having three dimensions. It has length, height and depth. Some might say length, width and height, which we'll use here. In this case, the volume is the product of the three dimensions. Vbox = l x w x h
3: length, width, and height
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
By adding all three sides (length, breadth and height) all-together we get the linear dimensions of a box.
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
You do not have enough information to calculate all three box dimensions.
It sounds like you have already found the dimensions of the box.