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If a box has a height of 56 inches what would the length of the diagonal be?
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
How do you find the height of a rectangular box when length is 7 m and width is 5 m and diagonal length 10m?
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
The diagonal of a rectangular box is 12 inches long One side of the box is 8 inches long What is the length of the other side?
8.9
How long is the diagonal of the box whose length width and height are 50cm 50cm and 50cm respectively?
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)
What is the equation of a box 6 cm in length 8 cm in height and 10 cm in width?
A box has no equation. There are different equations for its volume, its surface area, the longest (principal) diagonal.
What is the diagonal length of a box 50 X 50?
If it is a 2-D box then 70.71
If a box has a height of 56 inches what would the length of the diagonal be?
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
How do you find the height of a rectangular box when length is 7 m and width is 5 m and diagonal length 10m?
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
What is the length of a diagonal of A box having dimensions 2 x 3 x 6?
36
The diagonal of a rectangular box is 12 inches long One side of the box is 8 inches long What is the length of the other side?
8.9
How long is the diagonal of the box whose length width and height are 50cm 50cm and 50cm respectively?
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)
What is the equation of a box 6 cm in length 8 cm in height and 10 cm in width?
A box has no equation. There are different equations for its volume, its surface area, the longest (principal) diagonal.
How do you find the volume of a cubical box when diagonal is given?
Cool question ! Answer - half it then cube it to prove it - an example for you if cube diagonal (not square diagonal) is 100, then using pythagoras theorm the square diagonal = 70.71068, If square the square diagonal = 70.71068, then using pythagoras theorm the side length = 50 therefore the volume = 50 ^ 3 = 25000 units works with any numbers
How long is the diagonal of the box whose length width and height are 30cm 24cmand 18cm respectively?
the equation is L^2= w^2 + h^2 + l^2 where L= length of diagonal, w=width, h=height, and l= length, L= sqrt( (30)^2 + (24)^2 + (18)^2)= (approx) 42.2 cm
A box is made in the shape of cube its dimension are of length 8cm what is the lenght oof longest pencil that would fit inside the box?
Use Pythagoras' theorem to find the length of the outer diagonal and then use this as the base for the inner diagonal (the longest length of the cube) 82+82 = 128 and the square root of this is 11.3137085 cm 11.31370852+82 = 192 and the square root of this is 13.85640646 cm The longest pencil is 13.85640646 or just under 14 cm
In badminton where does the serve have to land for it to be legal?
It has to land in the opposite diagonal service box (because you face the opposite diagonal service box when you are serving).
If a box is 120 centimeters long and 25 centimeters wide What is the length of the longest ski pole that could be packed to lie flat in the box?
The longest ski pole to fit would lie diagonally. The length of the diagonal can be found by the pythagorean theorem.d=sqrt(1202+252)d ~= 122.58 cm
