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If a box has a height of 56 inches what would the length of the diagonal be?
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
How do you find the height of a rectangular box when length is 7 m and width is 5 m and diagonal length 10m?
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
The diagonal of a rectangular box is 12 inches long One side of the box is 8 inches long What is the length of the other side?
8.9
How long is the diagonal of the box whose length width and height are 50cm 50cm and 50cm respectively?
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)
What is the equation of a box 6 cm in length 8 cm in height and 10 cm in width?
A box has no equation. There are different equations for its volume, its surface area, the longest (principal) diagonal.
