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If repetitions of digits is not allowed, then 5! (which is 5-factorial = 5*4*3*2*1). If you assume repetition of digits is allowed, then 55.
More detail:
The math category this falls under is called combinatorix - counting the number of ways to combine things. The first answer, 5!, comes from the following reasoning:
There are 5 possibilities for the first place. Once you have chosen that places, there are four choices remaining for the next digit for each of those choices, thus giving you 5*4, and thus logic continues for the remaining digits.
For the other answer, the logic is the same, but since there is repetition allowed, each places has 5 choices.
What else can I help you with?
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
How many numbers can you make with 3 7 8 9?
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
How many 6 number combinations can you make with numbers 1-50. No 1 number repeats?
The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700
How many 3 digit combinations are there in 1 to 21?
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
How many 2 number combinations are there in the numbers 1 to 9?
There are 9C2 = 9*8/(2*1) = 36 2-digit combinations.
What is the number of combinations for 2 out of 5 events?
There are 5C2 = 5*4/(2*1) = 10 combinations.
What is the Total number of 1 bit combinations are?
The total number of 1-bit combinations is 2. This is because a single bit can have two possible values: 0 or 1. Therefore, the combinations are {0, 1}.
How many 5 number combinations can you make from numbers 1 to 56?
There are 56C5 = 56*55*54*53*51/(5*4*3*2*1) = 3,819,816 combinations.
How many 4 digit combinations can you get from numbers 1226?
To calculate the number of 4-digit combinations you can get from the numbers 1, 2, 2, and 6, we need to consider that the number 2 is repeated. Therefore, the total number of combinations is calculated using the formula for permutations of a multiset, which is 4! / (2!1!1!) = 12. So, there are 12 unique 4-digit combinations that can be formed from the numbers 1, 2, 2, and 6.
How many different combinations can you make 1-10?
To find the number of different combinations of the numbers 1 to 10, we can consider the combinations of choosing any subset of these numbers. The total number of combinations for a set of ( n ) elements is given by ( 2^n ) (including the empty set). For the numbers 1 to 10, ( n = 10 ), so the total number of combinations is ( 2^{10} = 1024 ). This includes all subsets, from the empty set to the full set of numbers.
How many combinations can you make with 2 letters?
Assuming you are using the standard English alphabet, the number of combinations you can make are: 26 x 26 = 676 combinations.
How many combinations can you make from the numbers 1 2 3 4 5 not multiplying?
The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.
