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There are infinitely many sets that will satisfy the requirements.

Three examples are:

{0, 6, 8, 8, 8}

{2, 6, 6, 6, 10}

{√3, 5, 5, 12-2*√3, √3+8}

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Q: What 5 numbers have the mean of 6 and the range of 8?
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Related questions

What set of 5 numbers have 6 as the median 6 as the mean and 6 as the range?

3,5,6,7,9


What 5 numbers have a range of 4 a median of 5 and a mean of 6?

4, 5, 5, 8, 8


What five numbers have a median range and mean of 6?

3, 4, 5, 6, 7, 8, and 9.


What are 5 numbers when the range mean and median are six?

(3, 4, 6, 8, 9)


A set of data has 5 numbers has a range of six median of six and a mean of six what are the five numbers?

4 4 6 6 10


Which 2 numbers have a mean of 10 and a range of 8?

the two numbers that have a mean of 10 and a range of 8 is 6 and 14


What six numbers have a range of six and a mean of 6?

(3, 4, 5, 7, 8, 9)


What six numbers that have a range of six and a mean of 6?

3 (15/5), 21/5, 27/5, 33/5, 39/5, 9(45/5) Range = 9 - 3 = 6 Mean = (15/5 + 21/5 + 27/5 + 33/5 + 39/5 + 45/5)/6 = (180/5)/6 = 36/6 = 6


What ten numbers have a median of 5 a mode of 3 a range of 9 and mean of 5?

(1, 3, 3, 3, 5, 5, 6, 6, 8, 10)


What 4 numbers that have a mean of 4 and a range of 4?

1, 5, 5, and 5 5+5+5+1=16/4=4 5-1=4


What numbers have a mean of 5 a median of -1 and the range of 6?

It is easy to prove that such a set of numbers cannot exist. If the median is -1 and the mean is different from the median, then there must be at least one number that is less than or equal to -1. Then, if the range is 6, the largest number can only be 5. If the largest number is 5 and the mean is 5, then all the numbers must be 5. That is not possible because there is at least one that is -1 or smaller.


What five numbers have a median of 9 a mode of 10 a range of 5 and mean of 8?

5, 6, 9, 10, & 10