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How many recursive patterns can you find with 4 plus 7 as the first 2 terms?
Infinitely many. For example: Un+1 = Un + 3 or Un+1 = 2*Un - 1 or Un+1 = 3*Un - 5 or, more generally, Un+1 = k*Un + 7 - 4*k where k is any number. Each one of them will be different from the third term onwards. These are linear patterns. There are quadratic and other recursive relationships.
What 4 recursive patterns can you make starting with 4 and 7?
Starting with the numbers 4 and 7, you can create the following recursive patterns: Addition Pattern: Each term is the sum of the previous two terms, starting with 4 and 7 (e.g., 4, 7, 11, 18, 29, ...). Multiplication Pattern: Multiply the previous two terms to get the next one (e.g., 4, 7, 28, 196, ...). Alternating Addition/Subtraction Pattern: Alternate adding and subtracting the original numbers (e.g., 4, 7, 3, 10, 6, ...). Doubling Pattern: Start with 4, then double it, followed by adding 7 to the previous term (e.g., 4, 8, 15, 30, ...).
Is 1-4-9-16-25-36 a recursive pattern?
no it is not a recursive pattern because it isn't equal numbers.
What is the recursive formula for 1 4 13 40 121?
The sequence 1, 4, 13, 40, 121 can be described by a recursive formula. The recursive relationship can be expressed as ( a_n = 3a_{n-1} + 1 ) for ( n \geq 2 ), with the initial condition ( a_1 = 1 ). This means each term is generated by multiplying the previous term by 3 and then adding 1.
Which represents the first three terms of the sequence a1 2 and an 4(an-1)2?
Becasue the browser used by this site is unable to display most mathematical notation, this may not be the correct recursive formula, but:if a(1) = 2 and a(n) = 4*a(n-1)^2 then then a(2) = 4*2^2 =4*4 =16 and a(3) = 4*4^2 = 4*16 = 64
How many different recursive patterns can you find with 4 and 7 as the first 2 terms?
there are 4 different ways you can do it
What is the recursive definition of 8 4 2 1?
8/4/2=1
How many recursive patterns can you find with 4 plus 7 as the first 2 terms?
Infinitely many. For example: Un+1 = Un + 3 or Un+1 = 2*Un - 1 or Un+1 = 3*Un - 5 or, more generally, Un+1 = k*Un + 7 - 4*k where k is any number. Each one of them will be different from the third term onwards. These are linear patterns. There are quadratic and other recursive relationships.
Is 4 9 19 39 79 159 recursive?
no it is not recursive
What 4 recursive patterns can you make starting with 4 and 7?
Starting with the numbers 4 and 7, you can create the following recursive patterns: Addition Pattern: Each term is the sum of the previous two terms, starting with 4 and 7 (e.g., 4, 7, 11, 18, 29, ...). Multiplication Pattern: Multiply the previous two terms to get the next one (e.g., 4, 7, 28, 196, ...). Alternating Addition/Subtraction Pattern: Alternate adding and subtracting the original numbers (e.g., 4, 7, 3, 10, 6, ...). Doubling Pattern: Start with 4, then double it, followed by adding 7 to the previous term (e.g., 4, 8, 15, 30, ...).
What is the recursive formula for 2 1 3 4 7 11?
It look like a Fibonacci sequence seeded by t1 = 2 and t2 = 1. After that the recursive formula is simply tn+1 = tn-1 + tn.
Is 1-4-9-16-25-36 a recursive pattern?
no it is not a recursive pattern because it isn't equal numbers.
What is the recursive formula for 1 4 13 40 121?
The sequence 1, 4, 13, 40, 121 can be described by a recursive formula. The recursive relationship can be expressed as ( a_n = 3a_{n-1} + 1 ) for ( n \geq 2 ), with the initial condition ( a_1 = 1 ). This means each term is generated by multiplying the previous term by 3 and then adding 1.
How can a recursive pattern go from 3 to 4 to 6 to 10 then 18?
t(1) = 3 t(n) = t(n-1) + 2(n-2) for n = 2, 3, 4, ...
What is the recursive formula for 64 to 16 to 4 to 1?
x_n+1 = x_n / 4
What is the recursive formula for -14 -8 -2 4 10?
t(n+1) = t(n) + 6 t(1) = -14
Which represents the first three terms of the sequence a1 2 and an 4(an-1)2?
Becasue the browser used by this site is unable to display most mathematical notation, this may not be the correct recursive formula, but:if a(1) = 2 and a(n) = 4*a(n-1)^2 then then a(2) = 4*2^2 =4*4 =16 and a(3) = 4*4^2 = 4*16 = 64
