1000, 1004, 1008 and just keep adding four until you get to 9996.
All of the four-digit multiples of 400 end in 00.
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
The digit of 4 in 0.004 represents 4/1000 = four thousandths
The first 4 multiples of 1 are: 1, 2, 3, and 4.
There are 90 four-digit palindromes
Multiples of 10 between 1000 and 9990 Any four-digit number ending in zero.
67 of them.
All of the four-digit multiples of 400 end in 00.
8100
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.
4500 of them.
Four has an infinite number of multiples.
-4
Well, honey, to find the number of 4-digit multiples of 9, you just need to divide the largest 4-digit multiple of 9 (9999) by 9 and subtract the smallest 4-digit multiple of 9 (1008) divided by 9. So, 9999 ÷ 9 - 1008 ÷ 9 = 1111 - 112 = 999. That's right, there are 999 4-digit numbers that are multiples of 9.
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
There are more than four, starting with 12, 15, 18 and 21.
The first four are; 4,8,12,16