All of the four-digit multiples of 400 end in 00.
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
The digit of 4 in 0.004 represents 4/1000 = four thousandths
The first 4 multiples of 1 are: 1, 2, 3, and 4.
There are 90 four-digit palindromes
Multiples of 10 between 1000 and 9990 Any four-digit number ending in zero.
67 of them.
All of the four-digit multiples of 400 end in 00.
8100
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.
4500 of them.
Four has an infinite number of multiples.
-4
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
To find the number of 4-digit numbers that are multiples of 9, we first determine the range of 4-digit numbers, which is from 1000 to 9999. Next, we calculate the first and last multiples of 9 within this range, which are 1008 and 9999 respectively. To find the total number of multiples of 9 in this range, we divide the difference between the last and first multiples by 9 and add 1, resulting in (9999 - 1008) / 9 + 1 = 999. Therefore, there are 999 4-digit numbers that are multiples of 9.
There are more than four, starting with 12, 15, 18 and 21.
The first four are; 4,8,12,16