0
What are the centre and radius of a circle whose equation is 2x squared plus 2y squared plus 2x -6y -9 equals 0?
Wiki User
∙ 7y ago
Divide all terms by 2 and so: x^2 +y^2 +x -3y -4.5 = 0
Completing the squares for x and y: (x+1/2)^2 + (y-3/2)^2 -1/4 -9/4 -4.5 = 0
Therefore: (x+1/2)^2 + (y-3/2)^2 = 7
The centre of the circle is at (-1/2, 3/2) and its radius is the square root of 7
Wiki User
∙ 7y ago
Add your answer:
Earn +20 pts
How do you solve x squared plus y squared equals 13?
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 squared equals 25?
The centre is (-5, 3)
What is the centre and radius of a circle when x squared plus y squared -2ax -2ay equals 0?
The centre is (a, a) and the radius is a*sqrt(2).
What is the radius for a circle with the equation x2 plus y2 equals 9?
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
What is the radius equation inside the circle x squared plus y squared -8x plus 4y equals 30 that meets the tangent line y equals x plus 4 on the Cartesian plane showing work?
Circle equation: x^2 +y^2 -8x +4y = 30 Tangent line equation: y = x+4 Centre of circle: (4, -2) Slope of radius: -1 Radius equation: y--2 = -1(x-4) => y = -x+2 Note that this proves that tangent of a circle is always at right angles to its radius
How do you solve x squared plus y squared equals 13?
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 squared equals 25?
The centre is (-5, 3)
What is the centre and radius of a circle when x squared plus y squared -2ax -2ay equals 0?
The centre is (a, a) and the radius is a*sqrt(2).
What is the radius for a circle with the equation x2 plus y2 equals 9?
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
What is the radius equation inside the circle x squared plus y squared -8x plus 4y equals 30 that meets the tangent line y equals x plus 4 on the Cartesian plane showing work?
Circle equation: x^2 +y^2 -8x +4y = 30 Tangent line equation: y = x+4 Centre of circle: (4, -2) Slope of radius: -1 Radius equation: y--2 = -1(x-4) => y = -x+2 Note that this proves that tangent of a circle is always at right angles to its radius
Where is the center of the circle given by the equation x plus 4 squared plus y plus 6 squared equals 49?
(-4,-6)
What is the centre and radius of a circle when x squared plus y squared -4x -2y -4 equals 0?
Equation: x^2 +y^2 -4x -2y -4 = 0 Completing the squares: (x-2)^2 +(y-1)^2 -4-1-4 = 0 So: (x-2)^2 +(y-1)^2 = 9 Therefore the centre of the circle is at (2, 1) and its radius is 3
Does the equation a squared plus b squared equals c squared classify as a quadratic equation?
no
Where is the center of the circle given by the equation x - 3 squared plus y plus 2 squared equals 9?
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
How do you graph the equation x squared plus y squared equals 16?
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
What is the centre and radius of a circle embeded on the Cartesian plane whose equation is x squared plus y squared -4x -2y -4 equals 0 showing key aspects of work?
Note that: (x-a)2+(y-b)2 = radius2 whereas a and b are the coordinates of the circle's centre Equation: x2+y2-4x-2y-4 = 0 Completing the squares: (x-2)2+(y-1)2 = 9 Therefore: centre = (2, 1) and radius = 3
Is c equals 2πr the same as c equals πr squared?
No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).
