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50' in Length by 1' in Width...50 x 1 = 50 :: 50+50+1+1=102

Q: What are the dimensions of a rectangle that has a perimeter of 102 and an area of 50?

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length = 34 and width = 3 Perimeter = 34+34+3+3 = 74 Area = 34*3 = 102

Width = 3 Length = 34

Base = 102/12 = 8.5 feet Perimeter = 12+8.5+12+8.5 = 41 feet

It depends on the shape of your room. If your room is a rectangle then your perimeter is 102 feet.

10.1 × 10.1 = 102.01in2

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length = 34 and width = 3 Perimeter = 34+34+3+3 = 74 Area = 34*3 = 102

Width = 3 Length = 34

Base = 102/12 = 8.5 feet Perimeter = 12+8.5+12+8.5 = 41 feet

102 m

It depends on the shape of your room. If your room is a rectangle then your perimeter is 102 feet.

10.1 × 10.1 = 102.01in2

A rectangle has 2 sides and 2 widths5 x 2 = 102 x 2 = 410 + 4 = 14cm

(40/4)2 = 102 = 100m2.

You can't tell the length and width from the perimeter. There are an infinite number of of possibilities. The only thing you can tell for sure is that the length and width add up to 51 (assuming you are asking about a rectangle, other shapes could have much different lengths and widths). A circle with a perimeter of 102 has a length and a width of approximately, 32.268.

Answer 100 ---- If the perimeter of a square is 40 meters, then each side has lenght 10 meters. This is because the formula for perimeter is 4L where L is the lenght. Now, the area is L2 which is 102 =100

If the width of the rectangle is 14, then there are two sides of 14. Subtracting this from 130 gives 130 - (14 x 2) = 102. The two remaining sides, added together, must equal 102. Therefore, each side would equal 102/2 = 51. Don't forget to include the appropriate units in your answer.

To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.