Find two integers such that they add up of 19 and multiply altogether to get -60. We can't determine these values with these conditions since:
xy = -60
x + y = 19
y = -60/x
x - 60/x = 19
x² - 60 = 19x
x² - 19x = 60
x² - 19x + (-19/2)² = 60 + (-19/2)²
(x - 19/2)² = 601/4
Since 601/4 is not the perfect square term, there are no factors of 6n² + 19n - 10.
4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
Composite. It is divisible by 3 for any n.
51.07142857142857
6(n - 4)(n + 1) n = 4, -1
x2 + 3x + 2 factors into (x + 1) (x + 2)
2n(3n + 8)
(3m+2n)(m+3n)
4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
Composite. It is divisible by 3 for any n.
6n2 + 16n can be factorised to give 2n(3n + 8) so the highest factor is 2n.
6n2+6n+1
6n2
Factors of 6 are either 1 & 6 or 2 & 3, those of 4 are either 1 & 4 or 2 & 2. The only combination which gives the required sum and product is (2n + 1)(3n - 4)
(2x + 1)(x + 3) are the factors.
51.07142857142857
The factors of 72 are 1,2,3,4,6,8,9,12,18,24,36,72.
The factors are 2n(4n + 3).