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Find two integers such that they add up of 19 and multiply altogether to get -60. We can't determine these values with these conditions since:
xy = -60
x + y = 19
y = -60/x
x - 60/x = 19
x² - 60 = 19x
x² - 19x = 60
x² - 19x + (-19/2)² = 60 + (-19/2)²
(x - 19/2)² = 601/4
Since 601/4 is not the perfect square term, there are no factors of 6n² + 19n - 10.
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To find the factors of the trinomial (3m^2 + 11mn + 6n^2), we need to break it down into two binomials. First, we find two numbers that multiply to the product of the leading coefficient and constant term, which are (3 \times 6 = 18). Then, we look for two numbers that add up to the middle coefficient, which is 11. The factors are ((3m + 2n)(m + 3n)).
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Solve 6n2-18n-18 equals 6?
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