Best Answer

For the first letter, you can choose any of the four.

For the second letter, you can choose any of the remaining three.

For the third letter, you can choose either of the remaining two.

For the fourth letter, you don't get a choice, you have to use the one that's left.

So 4x3x2x1 = 24 possible permutations.

Q: What are the number of permutations of the letters of the word MATH?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

Since there are no duplicate letters in the word RAINBOW, the number of permutations of those letters is simply the number of permutations of 7 things taken 7 at a time, i.e. 7 factorial, which is 5040.

There are 7 factorial, or 5040 permutations of the letters in the word NUMBERS.

three

7 factorial

239,500,800 12!/2! * * * * * Actually, as the word "permutation" [not permutations] has 11 letters, the answer is 11!/2! = 19,958,400

Related questions

Since the word MATH does not have any duplicated letters, the number of permutations of those letters is simply the number of permutations of 4 things taken 4 at a time, or 4 factorial, or 24.

The solution is count the number of letters in the word and divide by the number of permutations of the repeated letters; 7!/3! = 840.

The number of permutations of the letters in the word LOUISIANA is 9 factorial or 362,880. However, since the letters I and A are each repeated once, you need to divide that by 4 to determine the number of distinct permutations, giving you 90,720.

UNITED = 6 letters The letters in the word UNITED did not repeat so the number of permutations = 6! = 6x5x4x3x2 =720

The number of permutations of the letters in the word SCHOOLS is the number of permutations of 7 things taken 7 at a time, which is 5040. However, since two of the letters, S and O, are duplicated, the number of distinct permutations is one fourth of that, or 1260.

The number of permutations of the letters SWIMMING is 8 factorial or 40,320. The number of distinct permutations, however, due to the duplication of the letters I and M is a factor of 4 less than that, or 10,080.

Since there are no duplicate letters in the word RAINBOW, the number of permutations of those letters is simply the number of permutations of 7 things taken 7 at a time, i.e. 7 factorial, which is 5040.

360. There are 6 letters, so there are 6! (=720) different permutations of 6 letters. However, since the two 'o's are indistinguishable, it is necessary to divide the total number of permutations by the number of permutations of the letter 'o's - 2! = 2 Thus 6! ÷ 2! = 360

The number of permutations of the letters PENCIL is 6 factorial, or 720.

The word MATHEMATICS has 11 letters. The number of permutations of 11 things taken 11 at a time is 11 factorial (11!), or 39,916,800.

There are 6! = 720 permutations.

If you mean permutations of the letters in the word "obfuscation", the answer is 1,814,400.