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If y = 3x + 1 is a tangent to x² + y² = k (k > 0 since it is a square), then where they meet has a repeated root; they meet at:

x² + (3x + 1)² = k

→ x² + 9x² + 6x + 1 - k = 0

→ 10x² + 6x + (1 - k) = 0

This is the point of contact when it has a repeated root which is when the discriminant is zero, ie when:

6² + 4 × 10 × (1 - k) = 0

→ 36 + 40 - 40k = 0

→ 40k = 4

→ k = 1/10

I guess for x & y you mean the point where y = 3x + 1 is a tangent to x² + y² = k, ie the point of contact.

The value of k can now be substituted into the equation of the point of contact:

10x² + 6x + (1 - k) = 0

→ 10x² + 6x + (1 - 1/10) = 0

→ 10x² + 6x + 9/10 = 0

→ x² + 6x/10 + 9/100 = 0

→ (x + 3/10)²

→ The point of contact is when x = -3/10

→ y = 3× -3/10 + 1 = 9/10 + 1 = 1/10

→ point of contact is (-3/10, 1/10) with k = 1/10

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Q: What are the values of x y and k when the line y equals 3x plus 1 is a tangent to the circle x squared plus y squared equals k?
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