-2
If: y = c +x and y = 3 -x -5x^2
Then: c +x = 3 -x -5x^2
Transposing terms: 5x^2 +2x +(c -3) = 0
Using tangent discriminant formula: c = 3.2
Using quadratic equation formula: x = -0.2
By substitution the value of y is: 3
Therefore the values of the variables are: c = 3.2, x = -0.2 and y = 3
(x, y) = (-3, -3) or (3, 3)
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
The value of such an expression depends on the values assigned to the variables, in this case, x and c.
If: y = x-4 and y = x2+y2 = 8 then 2x2-8x+8 = 0 and the 3 ways of proof are: 1 Plot the given values on a graph and the line will touch the curve at one point 2 The discriminant of b2-4ac of 2x2-8x+8 must equal 0 3 Solving the equation gives x = 2 or x = 2 meaning the line is tangent to the curve
If: y = kx+1 then by using the discriminant y = 2x+1 If: y = 2x+1 then y^2 = (2x+1)^2 or 4x^2 +4x +1 If y^2 = 4x^2 +4x +1 and y^2 = 8x Then: 4x^2 +4x +1 = 8x or 4x^2 -4x +1 = 0 Factorizing the above: (2x-1)(2x-1) = 0 meaning x = 1/2 By substitution into the original equations: y = 2 Therefore the values of the 3 variables are: k = 2, x = 1/2 and y = 2
If: y = kx -2 and y = x^2 -8x+7 Then the values of k work out as -2 and -14 Note that the line makes contact with the curve in a positive direction or a negative direction depending on what value is used for k.
(x, y) = (-3, -3) or (3, 3)
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
Because the variables of x and a have different values so they can't be equal.
The value of such an expression depends on the values assigned to the variables, in this case, x and c.
If: y = x-4 and y = x2+y2 = 8 then 2x2-8x+8 = 0 and the 3 ways of proof are: 1 Plot the given values on a graph and the line will touch the curve at one point 2 The discriminant of b2-4ac of 2x2-8x+8 must equal 0 3 Solving the equation gives x = 2 or x = 2 meaning the line is tangent to the curve
If: y = kx+1 then by using the discriminant y = 2x+1 If: y = 2x+1 then y^2 = (2x+1)^2 or 4x^2 +4x +1 If y^2 = 4x^2 +4x +1 and y^2 = 8x Then: 4x^2 +4x +1 = 8x or 4x^2 -4x +1 = 0 Factorizing the above: (2x-1)(2x-1) = 0 meaning x = 1/2 By substitution into the original equations: y = 2 Therefore the values of the 3 variables are: k = 2, x = 1/2 and y = 2
Since the word 'equals' appears in your questions it might be what is called a trigonometric identity, in other words a statement about a relationship between various trigonometric values.
Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.
Using the discriminant the possible values of k are -9 or 9
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
When you graph a tangent function, the asymptotes represent x values 90 and 270.